Since they are both positively charged, then the force would in fact be repulsion, because they are both the same. If you were to have one positively charged, and one negatively charged, then they would go towards eachother.
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Answer:
<em>displacement = -85 miles</em>
Explanation:
<u>Displacement
</u>
It's a magnitude used to measure the linear space between two points. It's computed as the subtraction of the final position minus the initial position which results in a vector. Notice the displacement only depends on the initial and final positions and not on the path the object has traveled.
Brayden starts to measure his position when the mile marker reads 260. Then he travels to the 150-mile marker and goes back to the 175-mile marker, his final position. As mentioned, the displacement only depends on the relative positions, so
displacement = 175 - 260 = -85 miles
Answer:
X = 6910319.7 m
Explanation:
let X be the distance where the acceleration of gravity is 85% of what it is on the surface and g1 be the acceleration of gravity at the surface and g2 be the acceleration of gravity at some distance X above the surface.
on the surface of the earth, the gravitational acceleration is given by:
g1 = GM/(r^2) = [(6.67408×10^-11)(5.972×10^24)]/[(6371×10^3)^2] = 9.82 m/s^2
at X meters above the earth's surface, g2 = 85/100(9.82) = 8.35m/s^2
then:
g2 = GM/(X^2)
X^2 = GM/g2
X = \sqrt{GM/g2}
= \sqrt{(6.67408×10^-11)(5.972×10^24)/ 8.35
= 6910319.7 m
Therefore, the acceleration of gravity becomes 85% of what it is on the surface at 6910319.7 m .
