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nignag [31]
3 years ago
10

There is 200 students.The ratio of girls to boys is 5 to 3. what is the percent of students are boys? 

Mathematics
2 answers:
Viktor [21]3 years ago
7 0
There would be a ratio of of 3/5 boys to girls. 3/5 of 200 is 120
I feel like that's irrelevant because those numbers don't add up.
Take 1 unit so 1/8 then factor it into 200.
you get 25
25*3 is 75.
75 is 37.5% of 200
Give Tristan a Brainliest, he deserves it. :p
skelet666 [1.2K]3 years ago
4 0
The percentage of male students is 37.5%

- There for every five girls there are three boys.

- That is eight students per.

- I took two hundred and divided it by eight to get twenty-five.

- I got twenty five, if you take twenty-five times three you get seventy-five & if you take twenty-five times five you get one hundred twenty-five.

- Add those two products and you'll have your two hundred.

- So, take seventy-five over two hundred to get thirty-seven and a half.

- Divide that by one hundred to get the ratio.

- It comes out to 37.5%
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Fantom [35]
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3 years ago
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Please review the following attachment. Thanks!
vaieri [72.5K]

Answer:

C: I and III only.

Step-by-step explanation:

We have two numbers x and y such that:

-y

And we want to determine which of the following conditions must be true.

First, let's examine the third condition. We have:

y>0

To see if this is true, let's try a negative value for y. So, let's use -7. This will give:

-(-7)

Simplify:

7

This is saying we need a number less than -7 and greater than 7.

This is impossible. So, y <em>must be</em> greater than 0.

Therefore, Condition III must be true.

Next, let's see this compound inequality visually.

Picture the following number-line:

<----------(-y)----------0----------y---------->

Whatever y is, -y is just y on the negative side.

Now, since our condition is that -y<x<y, this means that our x can be anywhere between -y and y. Namely:

<----------(-y)----------0----------y---------->

To determine our correct condition, let's picture x anywhere on the bolded lines. I'm just going to put x here...

<----------(-y)-------(x)--0----------y---------->

Now, remember the alternative definition for absolute value. Namely, the absolute value of x is also the <em>distance</em> from 0 to x. And this distance is always positive.

Since our x is between -y and y, our distance from 0 to x will always be less than the distance from 0 to either y.

Therefore, Condition I is also true.

Let's try an example. Let's let y = 9. So, -y=-9. And let's let x be between 9 and -9, say, -2. So:

<---(-9)-----(-2)--0--------(9)------>

We can see that:

|-2|=2\stackrel{\checkmark}{

Also, this example counters Condition II, as our x can indeed be negative if we desire it.

Algebraically, if we have a negative x such that:  

-y

We can divide everything by -1 to obtain:

y>x>-y

We can flip this to get:

-y

Which is our original inequality. So, Condition II does not need to be true.

So, the two conditions that <em>must</em> be true is I and III.

So, our answer is C.

3 0
3 years ago
Plz help me asap plz i will mark you as brainlist
Masteriza [31]

Answer:

$420

Step-by-step explanation:

130x12=1560

165x12=1980

1980-1560=420

4 0
3 years ago
Read 2 more answers
Please answer giving Brainliest
yarga [219]
I can’t find the answer. Are you sure this is the whole question?
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1 year ago
HELP I DONT KNOW THESE :(
Leya [2.2K]
The answer is -1 and 2
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3 years ago
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