Ask question

Ask question

All categories

2 years ago

10

There is 200 students.The ratio of girls to boys is 5 to 3. what is the percent of students are boys?

2 answers:

Viktor [21]2 years ago

7 0

There would be a ratio of of 3/5 boys to girls. 3/5 of 200 is 120
I feel like that's irrelevant because those numbers don't add up.
Take 1 unit so 1/8 then factor it into 200.
you get 25
25*3 is 75.
75 is 37.5% of 200
Give Tristan a Brainliest, he deserves it. :p

skelet666 [1.2K]2 years ago

4 0

The percentage of male students is 37.5%

- There for every five girls there are three boys.

- That is eight students per.

- I took two hundred and divided it by eight to get twenty-five.

- I got twenty five, if you take twenty-five times three you get seventy-five & if you take twenty-five times five you get one hundred twenty-five.

- Add those two products and you'll have your two hundred.

- So, take seventy-five over two hundred to get thirty-seven and a half.

- Divide that by one hundred to get the ratio.

- It comes out to 37.5%

You might be interested in

(It's late cuz no one answered it. Please Solve! I already posted this so don't answer both questions for points.)

earnstyle [38]

Answer: The slope is 80.75.

Step-by-step explanation: You just use the formula for rise over run.

7 0

3 years ago

Antoine works in a restaurant and he is paid his regular hourly rate of 40 hours a week and time and a half for all hours over 4

Inessa05 [86]

560+ 147= 707

14(40)= 560
14+ 14(1/2)=21
21(7)= 147

6 0

2 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

2 years ago

Could somebody help me im slow sorry

Mars2501 [29]

Answer:

I'd say multiply the numerators then the denominators and at the end simplify at least thats how I multiply fractions :)

8 0

2 years ago

Solve the following equation for x to find the total number of people who became members of a social networking site for a certa

zavuch27 [327]

Answer:

360 people

Step-by-step explanation:

x = 0.8x + 72 Subtract 0.8x on both sides

0.2x = 72 Divide 0.2 on both sides

x = 360

5 0

3 years ago

Read 2 more answers