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3 years ago

PLZ HELP A GIRL OUT !!! GIVIN BRAINIEST !!!

Mathematics

2 answers:

tekilochka [14]3 years ago

7 0

Answer:

Step-by-step explanation:

because the par is 1 so it turns tonegative

zhenek [66]3 years ago

4 0

the answer is A.

the equation is f(n-1)+2. f is -6 and n is the number of term. so for example, if you want to find the second term, you substitute n for 2. then you solve.

-6(2-1)+2,

-6(1)+2,

-6+2= -4. therefore the second term is -4. you do this with n being 1,3,4,5 to get the sequence of

2, -4, -10, -16, -22.

hope this helped !!

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3 years ago

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Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

Answer:

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

Solution:

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$

So, the equation is $x^{3}-2 x^{2}-x+2=0$

Let us put x = 0 in f(x) to check whether our answer is correct or not.

$\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2$

Hence, the equation of the polynomial is $x^{3}-2 x^{2}-x+2=0$

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