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posledela
3 years ago
12

James is 13 years older than one half of Abby's age. Monica is one year younger than four times Abby's age. If James and Monica

are the same age, how old are they
Mathematics
2 answers:
Andrej [43]3 years ago
8 0
J = 13+0.5A
M = 4A - 1
Since J = M you can just say
X = 13+0.5A
X = 4A - 1
Merge the equations by getting rid of one of the variables and solve for the remaining variable
Vika [28.1K]3 years ago
5 0
James and Monica are 15 years old and Abby is 4 years old.
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aksik [14]

Answer:

Could you please put a link to the question???

Step-by-step explanation:

We can only solve the question if you give us more info about the question.

8 0
3 years ago
PLEASE HELP!!!!!!
quester [9]

B

First you have to change 2 1/2 into 5/2

To multiply fractions use the method
Keep Change Flip

5/2 x 3/1 =15/2

Which simplifies to 7 1/2
6 0
3 years ago
Read 2 more answers
753% in a decimal form<br> :)
sasho [114]

ANSWER: 7.53

Step-by-step explanation:

To convert a percent to decimal you need to divide the percent by 1,

753% ÷ 1 = 7.53

7 0
3 years ago
. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir
mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

      P(U |D ) = 0.198

b

   P(O\ n \ B) = 0.188

c

  P(O | B) =   0.498

Step-by-step explanation:

The total number of deaths is mathematically represented as

      T   =  16 +  23 + \cdots  +  16

        T   =623

The total number of deaths in 1996 - 2000 is mathematically represented as

     T_a =  16 +  23+ \cdots + 30

      T_a = 235

The total number of deaths in 2001 - 2005 is mathematically represented as

     T_b =  17 +  16 + \cdots + 23

      T_b = 206

The total number of deaths in 2006 - 2010 is mathematically represented as

     T_c =  15 +  17 + \cdots + 16

      T_d = 182

Generally the the probability that it would occur under the tree given that the death was  after  2000 is mathematically represented as

     P(U |D ) = \frac{P(A \ n\  U )}{P(A)}

Here  P(A \ n\  U ) represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

         P(A \ n\  U )   = \frac{Z}{ T}

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

         Z =  35 +  42

=>       Z =  77

=>       P(A \ n\  U )   = \frac{77}{ 623}

=>      

Also

     P(A) is the probability of the death occurring after 2000  and this is mathematically represented as

        P(A) =  \frac{T_b  +  T_c}{ T}

=>      P(A) =  \frac{ 206+  182}{623}

=>  

So

         P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+  182}{623}}

=>      P(U |D ) = 0.198

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

      P(O | B) = \frac{T_z}{ T}

Here T_z is the total number of death outside / camping before 2001  and the value is  117  

So

            P(O \ n \ B) = \frac{117}{623}

=>          P(O\ n \ B) = 0.188

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

       P(O | B) =  \frac{ P( O \ n \ B)}{ P(B)}

Here P(B) is the probability that it was before 2001 , this is mathematically represented as  

          P(B ) =  \frac{T_a}{T}

=>       P(B ) =  \frac{235}{623}

So

          P(O | B) =  \frac{ \frac{117}{623}}{ \frac{235}{623}}

=>       P(O | B) =   0.498

5 0
3 years ago
1. what would the effect have been on the calculated formula weight ([9] above) of your unknown as compared to the true formula
kramer

If the solution is blue-green, this indicates that some copper is still present in the solution and that not all of it has precipitated. Expect it to be too low because you will have less mass.

With very few exceptions, all copper(I) (cuprous) compounds are diamagnetic and colorless. Cu2O, Cu2Cl2, and cuprous sulfide are a few of the significant commercial compounds of copper(I) (Cu2S).

The molar mass of the element copper is determined by looking at its average atomic mass, which is 63.55 AMU on the periodic table. Since it is also our molar mass, we will now put it in a different unit: grams over moles (63.55 gmol). That is copper's molar mass.

If the solution is blue-green, there is still copper in the solution and not all of it has precipitated. Because you will have less bulk, anticipate it to be too low.

To know more about copper, refer to this link:

brainly.com/question/1543891

#SPJ4

3 0
11 months ago
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