2 years ago

If I make 65000 a year and 40 hours a week. How much do I make in a hour?

Mathematics

1 answer:

max2010maxim [7]2 years ago

7 0

Answer:

$31.25

Step-by-step explanation:

40x 52 = 2080 65000/2080= $31.25

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vredina [299]

Answer:Magnitude of voltage is 41.9963 volts

Step-by-step explanation:

Given that current I =5.772-5.323i mA

and impedance, Z=3.342+4.176i kilo ohms

Then voltage in the circuit = IZ

$=(5.772-5.323i)X10^{-3}X(3.342+4.176i)X10^{3}$

$V=(5.772-5.323i)X(3.342+4.176i)$

$V=19.290024+24.103872i-17.789466i-23..5148848i^{2}$

$V=41.518892+6.314406i$

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3 years ago

Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

$\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)$

$f'(y)=0\implies f(y)=C$

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With $y(1)=2$ , we have

$8+\ln9=C$

$\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}$

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2 years ago

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IceJOKER [234]

Answer:

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Step-by-step explanation:

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3 years ago

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jenyasd209 [6]

Answer:

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Step-by-step explanation:

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3 years ago

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IceJOKER [234]

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3 years ago

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