This scatter diagram shows the marks scored in a class test in English and Science
1 answer:
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To find the area of his exclusion zone you would need to understand that a triangle with dimensions of 3, 4, and 5 represent a right triangle.
This means the exclusion zone would be applied to the base and the height of the triangular space.
You would add 2 km to the 3 km, and 2 km to the 4 km to create a new height of 5 km and a new base of 6 km.
Please see the attached picture to understand this.
You will find the area of the total space created by the new triangle and subtract the space represented by the original triangle to find the area of the exclusion zone.
(1/2 x 6 x 5) - (1/2 x 4 x 3)
15 km² -6 km² equals 9 km².
The exclusion space is 9 km².
This means the exclusion zone would be applied to the base and the height of the triangular space.
You would add 2 km to the 3 km, and 2 km to the 4 km to create a new height of 5 km and a new base of 6 km.
Please see the attached picture to understand this.
You will find the area of the total space created by the new triangle and subtract the space represented by the original triangle to find the area of the exclusion zone.
(1/2 x 6 x 5) - (1/2 x 4 x 3)
15 km² -6 km² equals 9 km².
The exclusion space is 9 km².
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Answer:
x = 67.5
Step-by-step explanation:
Because AB and NP lines are parrallel, we can find out the scale factor by dividing size MA by MN.
This works because you find out what the MA size has to be multiplied to to get to MN, which will also work in reverse to find angle MB from MP.
71.5 - 22 = MA = 49.5
71.5 ÷ 49.5 =
So to get to line MP length, line MB had to be multiplied by to get 97.5
The reverse of this is dividing 97.5 by :
97.5 ÷ = 67.5
So x = 67.5
<h2>Hope this helps!</h2>