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SSSSS [86.1K]
3 years ago
15

Randomly selecting a seventh grader from a school that has 250 sixth graders, 225 seventh graders, and 275 eighth graders

Mathematics
2 answers:
svlad2 [7]3 years ago
6 0

Answer: The probability is P = 0.32

Step-by-step explanation:

Here i guess that the question is: "what is the probability of randomly selecting a seventh-grader".

The data that we have is:

We have 250 sixth graders, 225 seventh graders and 275 eight graders, this adds to a total of 700 options.

The probability of randomly selecting a seventh-grader is equal to the number of seventh-graders divided the total number of possible options, in this case, 700.

So we have P = 225/700 = 0.32

This means that the probability of randomly selecting a seventh-grader is equal to 0.32

Alla [95]3 years ago
5 0
250 + 225 + 275 = 750 in total so 1/750
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Standard form of the equation that goes through (1, 2) with a slope of 7, please!
Radda [10]

Answer:

7x - y = 5

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Obtain the equation in point- slope form and rearrange into standard form.

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = 7 and (a, b) = (1, 2)

y - 2 = 7(x - 1) ← in point- slope form

y - 2 = 7x - 7 ( subtract y from both sides )

- 2 = 7x - y - 7 ( add 7 to both sides )

5 = 7x - y , that is

7x - y = 5 ← in standard form

7 0
3 years ago
Find an ordered pair that represents the vector from (-3.7,2) to (-4, -5).
Svetradugi [14.3K]

\bf \stackrel{\textit{component form of a vector}}{(a,b),(c,d)\implies } \\\\\\ (-3.7,2),(-4,-5)\implies \implies  \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill ~\hfill

3 0
3 years ago
Find the median mode range and any outliers. Then describe the data using them 77777,88,555,6,99,10101010,12
umka2103 [35]

Answer:

The median = 5

The mode  = 7

Range = 5

Outliers= None

Step-by-step explanation:

The median is the  value of the middle term.

The median is that value which divides the data into two equal halves.

7,7,7,7,7,8,8,5,5,5,6,9,9,10,10,10,10,12

There are 18 terms . So the middle term would be 9th term value= 5

The mode is the value which is repeated the most. = 7

Range is the difference between the highest and lowest value.= 12- 7= 5

The interquartile range, IQR= q3 - q1 where q3= 10 and q1= 7

IQR= 10 −7=3

The inner fences can be found out by

q1−(1.5*IQR) and q3+(1.5*IQR)

=7−(1.5*3) and 10+(1.5*3)

Inner fences: 2.5 and 14.5

The outer fences are q1−(3*IQR) and q3+(3*IQR)

=7−(3*3) and 10+(3*3)

Outer fences: -2 and 19

So if there are any outliers in this data set, they will either be less than -2 or greater than 19. But there are no outliers.

6 0
3 years ago
Nate starts a lawn-mowing business. In his business, he has expenses and revenue. Nate's expenses are the cost of the lawn mower
Korolek [52]

The question is incomplete. The complete question is :

Nate starts a lawn-mowing business. In his business, he has expenses and revenue. Nate's expenses are the cost of the lawn mower and gas, and his revenue is $25 per lawn. At what point will Nate's revenue exceed his expense?

Cost of lawn mower = $ 200

Cost of gasoline = $ 2 per lawn

Solution :

Given :

Cost of the lawn mower = $ 200

The cost of gasoline expense for one lawn = $ 2

The revenue generated for one lawn = $ 25

So let the number of lawn to be mowed = x

Therefore the total expenses = $200+2x$

So, the total revenue = $25x$

The point for which the revenue will exceed the total expenditure will be :

$25x \geq 200+2x$

So at x=9,  \ 225 > 218

Thus the revenue exceeds the total expenditure after mowing 9 number of lawns.

8 0
3 years ago
Read 2 more answers
Please help with both questions the person with the correct answers will get brainliest
Andreyy89
I think it’s number 7 is A and number 8 is C
8 0
3 years ago
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