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djverab [1.8K]
4 years ago
14

To calculate density, both _____ must be measured

Physics
2 answers:
erastova [34]4 years ago
6 0
Weight and volume !!!!
shutvik [7]4 years ago
3 0
Its mass and volume, mass is more specific than weight
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7 0
3 years ago
Noah is loading the ark and the last animal on board is a stubborn 1500-kg elephant who refuses to budge. Noah and his family pu
Oxana [17]

The coefficient of sliding friction is 0.514

Explanation:

We start by writing the equations of motion of the elephant along the two directions, parallel and perpendicular, to the incline.

Along the parallel direction we have:

F- mg sin \theta - \mu_k R = ma (1)

where :

F = 10,000 N is the force applied by Noah

mg sin \theta is the component of the weight parallel to the incline, where:

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

\theta=10^{\circ}  is the angle of incline

\mu_k R is the force of friction, where:

\mu_k is the coefficient of friction

R is the normal reaction  

and a is the acceleration

Perpendicular direction:

R-mg cos \theta =0 (2)

where mg cos \theta is the component of the weight perpendicular to the incline

From (2) we find

R=mg cos \theta

And substituting into (1)

F-mg sin \theta - \mu_k mg cos \theta = ma

We know that the elephant moves at constant speed, so the acceleration is zero:

a = 0

So the equation becomes

F-mg sin \theta - \mu_k mg cos \theta=0

And we can re-arrange it to find the coefficient of friction:

F-mg sin \theta - \mu_k mg cos \theta=0\\\mu_k = \frac{F-m g sin \theta}{mg cos \theta}=\frac{10000-(1500)(9.8)(sin 10)}{(1500)(9.8)(cos 10)}=0.514

Learn more about friction and inclined planes:

brainly.com/question/5884009

#LearnwithBrainly

4 0
3 years ago
Explain how sound travels through the air to observer
Harlamova29_29 [7]
Sample:
As soon as the lightning is seen, sound travels in the air for several kilometers until it eventually reaches the observer.
3 0
4 years ago
A rectangular wire loop is pulled out of a region of uniform magnetic field B at a constant speed v. What is true about the indu
Paul [167]

Answer:

There is a constant emf induced in the loop.

Explanation:

In the uniform magnetic field suppose the rectangular wire loop of length L and width b is moved out with a uniform velocity v. suppose any instance x length of the loop is out of the magnetic field and L-x length is inside the loop.

Area of loop outside the field = b(L-x)

we know that flux φ= BA

B= magnitude of magnetic field , A=  area

and emf \epsilon= \frac{d\phi}{dt}

\epsilon=B\frac{dA}{dt}

\epsilon=B\frac{db(L-x)}{dt}

\epsilon=Bb\frac{d(L-x)}{dt}

B,b and L are constant and dx/dt = v

⇒ε = -Bbv

which is a constant hence There is a constant emf induced in the loop.

5 0
4 years ago
Which statement accurately describes the motion of the object in the graph above over 10 seconds? Group of answer choices The ob
timurjin [86]

Answer:

Object appears to move forward at 1 cm/sec, then the velocity drops to zero for 3 sec and then moves forward at 2 cm/sec     (11 - 3) / (10 - 6) = 2 cm/sec

7 0
3 years ago
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