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3 years ago

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A constant force of 12 N in the positive x direction acts on a 4.0-kg object as it moves from the origin to the point 6i-8j m. H

ow much work is done by the given force during this displacement

1 answer:

Serga [27]3 years ago

5 0

Answer:

Explanation:

Only force in the direction of motion does work

The force acts in the x direction

The x change of position was 6 m

W = Fd = 12(6) = 72 J

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Explanation:

Since, it is given that one hand completes 3.19 vibrations in 8.46 sec. Therefore, in one second the number of vibrations will be as follows.

$\frac{3.19}{8.46}$

= 0.377 vibrations

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Now, formula to calculate the speed is as follows.

v = $f \times \lambda$

or, $\lambda = \frac{v}{f}$

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Which of the following statements about the conservation of momentum is not correct? Momentum is conserved for a system of objec

Olin [163]

Answer:

wrong statement : Momentum is not conserved for a system of objects in a head-on collision.

Explanation:

In a head on collision of two objects , two equal and opposite forces are created at the point of collision . These two forces create two impulses in opposite direction which results in equal and opposite changes in momentum in each of them . Hence net change in momentum is zero. In this way momentum is conserved in head on collision of two objects.

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3 years ago

State coulombs law in word

amid [387]

<h2><em>state coulombs law in word</em></h2>

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<em><u>hope </u></em><em><u>it</u></em><em><u> helps</u></em>

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3 years ago

A 23.5 g piece of aluminum metal is initially at 100.0°C. It is dropped into a coffee cup-calorimeter containing 130.0 g of wate

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Answer: The molar heat capacity of aluminum is $25.3J/mol^0C$

Explanation:

$heat_{absorbed}=heat_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ .................(1)

where,

q = heat absorbed or released

$m_1$ = mass of water = 130.0 g

$m_2$ = mass of aluminiunm = 23.5 g

$T_{final}$ = final temperature = $26.0^oC=(273+26)K=299K$

$T_1$ = temperature of water = $23^oC=(273+23)K=296K$

$T_2$ = temperature of aluminium = $100^oC=273+100=373K$

$c_1$ = specific heat of water= $4.184J/g^0C$

$c_2$ = specific heat of aluminium= ?

Now put all the given values in equation (1), we get

$130.0\times 4.184\times (299-296)=-[23.5\times c_2\times (299-373)]$

$c_2=0.938J/g^0C$

Molar mass of Aluminium = 27 g/mol

Thus molar heat capacity = $0.938J/g^0C\times 27g/mol=25.3J/mol^0C$

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3 years ago

give an example of how someone may be misjudged about their athletic ability due to diversity in sports (age,ethnicity,gender et

Ipatiy [6.2K]

Here is just a few:

1. white guys cant jump like black guys therefore white guys shouldn't play basketball
2. men are stronger than women so men should weight lift
3.football is a manly sport therefore woman should not play it

*hope this helps(these are just examples I am not expressing my beliefs

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3 years ago