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strojnjashka [21]
3 years ago
6

Given def is 4 times smaller than abc find the length perimeter of abc and def.

Mathematics
1 answer:
nataly862011 [7]3 years ago
4 0
56.5 is the answer to your question


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Ray NP is angle bisector of angle MNQ and measure of angle PNQ= 2x+1. find measure of angle MNQ
statuscvo [17]

C.

An angle bisector splits angles into halves thus resulting in PNQ. The total angle is however twice the PNQ so 4x + 2.

Hope this helps.

5 0
3 years ago
Find (fog)(x) when f(x)=x^2-7x+12 and g(x)=3/x^2-16
Kazeer [188]

Answer:

f( \frac{3}{ {x}^{2} - 16 } ) =  ({\frac{3}{ {x}^{2} - 16 }})^{2}  - 7(\frac{3}{ {x}^{2} - 16 }) + 12 \\  =  \frac{9}{ {x}^{4} - 32 {x}^{2}  + 256 }  -  \frac{21}{ {x}^{2}  - 16}  + 12

4 0
2 years ago
A gym instructor has a total of 60 hand weights in her studio.Some of the hand weights are 3 pound weights and the rest are 5 po
Masja [62]

Answer:

35 5-lb weights and 25 3-lb weights

Step-by-step explanation:


6 0
3 years ago
Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms
miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
  • Notice the terms at gap of one term beginning from the first term .They are like \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} . Next term is obtained by multiplying half to the previous term .
  • Notice the terms beginning from 2nd term , 4,7,10,13 . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

\implies S_2=\dfrac{n}{2}[2a + (n-1)d]

Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

7 0
3 years ago
An ice-skating rink hosts different events on different days of the week they keep track of ages of the people who attended the
kirill [66]

Answer:

i think it is B

Step-by-step explanation:

4 0
3 years ago
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