Sum of geometric sequence
for the sum where the initial value is a₁ and the common ratio is r and the term is n
common ratio is -3
-5 times -3 is 15, -15 times -3=-45 etc
first term is -5
and we want the 8th term
the sum is 8200
2. 5 hours
3. $200
4. 9.5 hours. If it has to be whole numbers, 10 hours
Hope that helps!
<em>-scsb17hm</em>
You have a 1/3 chance each time you role
So 1/3 x 12 = 4 times that you would role a 5 or a 6
Answer:
12,434
Step-by-step explanation:
since after the decimal point the number ranges 0-4 it will nullify but if 5-9 it will add 1 to the number before the point
First you graph it using a graphing calculator, you look at the table of values to find out one point in which y= 0. The first one that comes up is when x=1.
If you don't have a graphing calculator you can use trial and error by inputing some numbers into x until you get y= 0.
Once you have an x value which makes y=0, you can start factorizing it.
you divide 6x3 +4x2 -6x - 4 into (x-1) which is when y =0
to get 6x2+10x+4
This can be used to write the polynomial as (x-1)(6x2 +10x+4)
you then factorize the second bracket, 6x2 +10x+4.
you can take the 2 outside to give you 2(3x2 +5x+2)
you can factorize this to become 2(3x+2)(x+1)
Now you just substitute your factorized second bracket into your unfactorized second bracket to give you 2(3x+2)(x+1)(x-1).
From this you can deduce that k= 1
