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kirill115 [55]
3 years ago
13

Paul is comparing two high-speed Internet service providers (ISPs) for his business. The graph represents the cost of each ISP a

s a function of t, the duration in months of a service contract.
A coordinate grid showing Internet Service Provider Cost, with Service Contract in months along the horizontal axis, and Total Cost in dollars along the y-axis. Two lines are graphed. One line is labeled I S P A and passes through (0, 180) and (12, 300). The second line is labeled I S P B and passes through (0, 0) and (12, 300).

If C(t) = 180 + 10t represents ISP A and C(t) = 25t represents ISP B, how long would the service contracts need to be for the total costs to be the same?

6 months
8 months
10 months
12 months
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
7 0

Answer:

12 months

Step-by-step explanation:

Theres an awful amount of needless information to get through.

Only the last paragrph is needed.

C(t) = 180 + 10t

C(t) = 25t

Set the equations equal

25t = 180 + 10t

Subtract 10t from both sides

15t = 180

Divide both sides by 15

t = 12

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Given:

Dimensions of a tank are 50 cm by 32 cm by 20 cm

The tank is full of water and sand

Ratio of volume of water to the volume of sand is 5:1

To find:

Volume of water in the tank in liters

Solution:

Without loss of generality, let,

Length of tank = 50 cm

Breadth of tank = 32 cm

Height of tank = 20 cm

Then, we have,

Total Volume of the tank = Length * Breadth * Height

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Cross multiplying, we have,

Volume of sand = (Volume of water)/5

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Volume of water + Volume of sand = Total Volume

Using the value, we obtained, we get,

Volume of water + (Volume of water)/5 = Total Volume

\Rightarrow (6 * Volume of water)/5 = Total Volume

Plugging in the value of total volume, we get,

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\Rightarrow Volume of water = \frac{32000*5}{6} cc

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We know that,

1 cc = 0.001 liters

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Thus, Volume of water in the tank is approximately 26.667 liters

Final Answer:

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