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kirill115 [55]
3 years ago
13

Paul is comparing two high-speed Internet service providers (ISPs) for his business. The graph represents the cost of each ISP a

s a function of t, the duration in months of a service contract.
A coordinate grid showing Internet Service Provider Cost, with Service Contract in months along the horizontal axis, and Total Cost in dollars along the y-axis. Two lines are graphed. One line is labeled I S P A and passes through (0, 180) and (12, 300). The second line is labeled I S P B and passes through (0, 0) and (12, 300).

If C(t) = 180 + 10t represents ISP A and C(t) = 25t represents ISP B, how long would the service contracts need to be for the total costs to be the same?

6 months
8 months
10 months
12 months
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
7 0

Answer:

12 months

Step-by-step explanation:

Theres an awful amount of needless information to get through.

Only the last paragrph is needed.

C(t) = 180 + 10t

C(t) = 25t

Set the equations equal

25t = 180 + 10t

Subtract 10t from both sides

15t = 180

Divide both sides by 15

t = 12

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Answer:

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6 0
3 years ago
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PLEASE HELP!!!!
dalvyx [7]

Answer:

The surface area of the pyramid in exact form is 64 +  64\sqrt{3} cm²

The approximated surface area of the pyramid is 174.9 cm²

Step-by-step explanation:

The surface area of the square pyramid is the sum of the area of the base and the area of the four triangular faces

In Δ EFD

∵ m∠EFD = 90°

∵ m∠FDE = 60°

∵ ED = 8 cm

- By using sine ratio to find FE

∵ sin(∠FDE) = \frac{FE}{ED}

∴ sin(60) = \frac{FE}{8}

- Multiply both sides by 8

∴ FE = 8 sin(60°)

∴ FE = 4\sqrt{3} cm

In Δ AED

∵ AE = ED

∵ m∠D = 60°

- In any isosceles Δ if measure of an angle is 60, then the

  triangle is equilateral Δ

∴ Δ AED is an equilateral Δ

∴ AD = 8 cm

∵ The pyramid has 4 identical triangular faces

∵ Area of each Δ = \frac{1}{2} × base × height

∵ AD is the base and FE is the height

∴ Area of each Δ = \frac{1}{2} × 8 ×  4\sqrt{3}

∴ Area of each Δ = 16\sqrt{3} cm²

∵ Surface area of the pyramid = Area of base + 4 area of a Δ

∵ Area of base = 8²

∴ Area of base = 64 cm²

∴ Surface area of the pyramid = 64 + 4 × 16\sqrt{3}

∴ Surface area of the pyramid = 64 +  64\sqrt{3}

The surface area of the pyramid in exact form is 64 +  64\sqrt{3} cm²

The approximated surface area of the pyramid is 174.9 cm²

6 0
3 years ago
X/-3+20=30 help me please
Svetllana [295]

if you're solving for x it's -30

steps: x/-3+20=30

first subtract 20 from both sides then you'll have

x/-3=10 then multiply both sides with -3

you should have x by itself and -30 on the other side

answer x=-30

7 0
3 years ago
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