A sequence which terminates is called

A = 1/2ha +1/2hb solve for b

meriva

Answer:

A=1+1+2ha+2hb

A=2+2ha+2hb

A=2ha+2+2hb

A=4ha+2hb

4 = 4

A=½

3 0

3 years ago

Item 10 Find the amount of time. I=$450, P=$2400, r=7.5%

Alex787 [66]

The answer is: "2.5 years" .
___________________________________________________
Note: I = P * r * t ; { " Interest = Principal * rate * time "} ;

→ Solve for "t" {"time", in years} ;

Divide each side of the equation by "{P * r}" ;
to isolate "t" on one side of the equation ;

→ I / (P * r) = {P * r * t) / (P * r} ;

to get: " I / (P * r) = t " ;

 ↔ t = I / (P * r) ;

Given: I = $450 ;

 P = $2400 ;

r = 7.5% = 7.5/100 = 0.075 ;

Plug in these values into the formula to solve for the time, "t" :

 → t = I / (P * r ) ;

= $450 / ($2400 * 0.075) ;

= $450 / ($2400 * 0.075) ;

= $450 / $180 ;

= $45 / $18 ;

= ($45 ÷ 9) / ($18 ÷ 9)

= $5 / $2 ;

= 2.5 ;

→ t = 2.5 years.
_______________________________________________________
The answer is: "2.5 years" .
_______________________________________________________

7 0

2 years ago

3) What is an equation for the line that passes through the coordinates (-1.2) and (7,6) ?

OLEGan [10]

Answer:

$y=\frac{1}{2} x+\frac{5}{2}$

Step-by-step explanation:

First find the slope using the slope using the given points. Remember that the slope is the change in y over the change in x.

$\frac{6-2}{7- (-1)}=\frac{4}{8}=\frac{1}{2}$

So now we have the equation $y=\frac{1}{2} x+b$ , and we need to find out what b is. We can do this by pointing a point (either one, but I'll use -1,2) into the equation

$2=\frac{1}{2}(-1)+b$

Rearrange the equation so it equals b

$\frac{5}{2}=b$

Put it together and that's the final equation!

$y=\frac{1}{2} x+\frac{5}{2}$

7 0

2 years ago

Please helppp if the slope of a line is 6 and a line is perpendicular to it, what is its slope?

astra-53 [7]

Answer:

-1/6

Step-by-step explanation:

flip the slope

$\frac{6}{1}$

becomes

$\frac{1}{6}$

now the slope is going down so it becomes negative

= -1/6

7 0

3 years ago

A company that produces dog food claims that its bags contain 11 kg of food. From

andriy [413]

By testing the hypothesis we can conclude that the bag does not contain 11 kg of food.

Given mean of 10.6 kg, population standard deviation of 0.6 and sample size of 25.

We are required to find whether the company is right in saying that their bags contain 11 kg of food.

First we have to make hypothesis.

$H_{0}$ :μ≠11

$H_{1}$ :μ=11

We have to use t statistic because the sample size is less than 30.

t=(X-μ)/s/ $\sqrt{n}$

We will use s/ $\sqrt{n}$ =0.6 because we have already given population standard deviation of weights.

t=(11-10.6)/0.6

=0.4/0.6

=0.667

Degree of freedom=n-1

=25-1

=24

T critical at 0.05 with degree of freedom 24=2.0639

T critical at 0.05 with degree of freedom is greater than calculated t so we will accept the null hypothesis.It concludes that the bags donot contain 11 kg of food.

Hence by testing the hypothesis we can conclude that the bag does not contain 11 kg of food.

Learn more about t test at brainly.com/question/6589776

#SPJ1

3 0

1 year ago