To find the factor a a polynomial from its roots, we are going to seat each one of the roots equal to

, and then we are going to factor backwards.
We know for our problem that one of the roots of our polynomial is -3, so lets set -3 equal to

and factor backwards:



is a factor of our polynomial.
We also know that another root of our polynomial is

, so lets set

equal to

and factor backwards:




(

is a factor of our polynomial.
We can conclude that there is no correct answer in your given choices.
Answer: 14/15 of a meter
Step-by-step explanation:
5 and 3 LCM is 15.
3/5 x 3 + 1/3 x 5= 9/15 + 5/ 15 = 14/15
Rates are used to measure a quantity over another.
<em>The 1.8 million cars use </em>
<em> liters each year</em>
Given

--- distance

First, we calculate the number (n) of gallons used by each car

Solve for n

So, we have:


Convert miles to kilometers



The number of gallons (N), used by all the cars is:


Convert to liters


In scientific notation to 2 decimal places, we have:

<em>Hence, the number of liters used is </em>
<em />
Read more about distance and rates at:
brainly.com/question/24659604
All real numbers is the correct answer.
Answer:Side x side x side
Step-by-step explanation:
Since it is usually equally sided, it would be SxSxS