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vekshin1
4 years ago
6

Triangles △ABC and △DFG are similar. The lengths of the two corresponding sides are 1.4m , and 56 cm. What is the ratio of the p

erimeters of these triangles ?
Mathematics
2 answers:
Marina CMI [18]4 years ago
6 0

Answer:

5:2

Step-by-step explanation:

We have been given that triangles △ABC and △DFG are similar. The lengths of the two corresponding sides are 1.4 m and 56 cm.

Since both triangles are similar, therefore all corresponding sides will have same proportion.

Let us find proportion of corresponding sides of both triangles.

1 meter = 100 centimeter

1.4 meter = 1.4* 100 centimeters = 140 centimeters.

\frac{\text{Side of triangle ABC}}{\text{Side of triangle DFG}}=\frac{140}{56}

\frac{\text{Side of triangle ABC}}{\text{Side of triangle DFG}}=\frac{5}{2}

The ratio of sides of △ABC to sides of△DFG is 5:2.

Since perimeter of a triangle is sum of lengths of three sides of the triangle and all sides of both triangle have the ratio 5:2, therefore, their perimeters will be in same ratio, that is 5:2.

Feliz [49]4 years ago
3 0
<h3>Answer:</h3>

5/2

<h3>Step-by-step explanation:</h3>

The ratio of perimeters is the same as the ratio of corresponding sides:

... (140 cm)/(56 cm) = 5/2

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1. -8(1+4x)+7x=-25-8x <br> 2. -5+6(x-7)=-40+5x<br> Could you show the work?
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Answer:

1. x=1

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Step-by-step explanation:

1. -8(1+4x)+7x=-25-8x

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3 years ago
Can someone help me please ASAP
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Answer:

<h2>140°</h2>

solution,

Let <DEF= x°

<CDE= 2x°

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90 + 145 + 115 + 2x + x + 160 = 720 \\ 510 + 3x = 720 \\3x + 510 = 720 \\ 3x + 510 - 510 = 720 - 510 \\ 3x = 210 \\  \frac{3x}{x}  =  \frac{210}{3}  \\ x = 70 \: degree

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< \: cde = 2x \\  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  = 2 \times 70 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 140 \: degree

Hope this helps...

Good luck on your assignment..

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0.67%

Step-by-step explanation:

2/300

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I attached your answer below...

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