I assume you mean one that is not rational, such as √2. In such a case, you make a reasonable estimate of it's position, and then label the point that you plot.
For example, you know that √2 is greater than 1 and less than 2, so put the point at about 1½ (actual value is about 1.4142).
For √3, you know the answer is still less than 4, but greater than √2. If both of those points are required to be plotted just make sure you put it in proper relation, otherwise about 1¾ is plenty good (actual value is about 1.7321).
If you are going to get into larger numbers, it's not a bad idea to just learn a few roots. Certainly 2, 3, and 5 (2.2361) and 10 (3.1623) shouldn't be too hard.
Then for a number like 20, which you can quickly workout is √4•√5 or 2√5, you could easily guess about 4½ (4.4721).
They're usually not really interested in your graphing skills on this sort of exercise. They just want you to demonstrate that you have a grasp of the magnitude of irrational numbers.
Answer:
Whats the riddle
Step-by-step explanation:
The ball is at a height of 14 feet after 1.17 and 0.64 seconds.
This is an example of a quadratic equation. Write out the equation with 14 in the place of the height. Then, set it equal to zero.
14 = 2 + 29t - 16t^2
0 = -16t^2 + 29t -12
Now, we can use the quadratic equation to solve.
A = -16
B = 29
C = -12
You will get the solutions of 1.17 and 0.64.
Answer:65,
Step-by-step explanation:
57.80 - 4.07
= 57.80 - 4.00 - 0.07
= 53.80 - 0.07
= 53.73
