The domain is the limits of the function. Since time doesnt go negative, start with 0. At time 0, the height is
-16(0)^2 + 144 = 144ft
Then, solve for t to find the upper limit for t, which is when the height is zero (since you're dropping the object).
-16t^2 + 144 = 0
-16t^2 = -144
t^2 = 9
t = sqrt(9)
t = 3
The domain is 0 to 3 seconds.
Answer:
dont listen to this kid its $30.00 on APEX
Step-by-step explanation:
Answer:
what grade you in
Step-by-step explanation:
giuhyiufhyeiufheoirgjuoeirgjuer
Answer:
6
Step-by-step explanation:
Answer:
a. 5
b. -3
Step-by-step explanation:
a. (5*(8^1/3 + 27^1/3)^3)^1/4
= ((40^1/3 + 135^1/3)^3)^1/4
≈ ((3.42 + 5.13)^3)^1/4
≈ (8.55^3)^1/4
≈ 625^4
= 5
b. 64^-1/3*(64^1/3 - 64^2/3)
= 0.25*(4 - 16)
= 1/4 or 0.25 *-12
= -12*1 / 4
= -12/4
= -3
Hope this helped :3
