7(4 + 5) = 63
28 + 35 fits the criteria for your question.
Answer:
4:18 pm
Step-by-step explanation:
An airport offers 2 shuttles that run on different schedules.If both shuttles leave the airport at 4:00 p.m.,at what time will they next leave theairport together.
Shuttle A leaves every 6 minutes
Shuttle B leaves every 9 minutes
Solution
To solve for when next both shuttles will leave the airport together, find the least common multiples of 6 minutes and 9 minutes
Shuttle A (every 6 minutes) = 6, 12, 18, 24
Shuttle B (every 9 minutes) = 9, 18, 27, 36
The least common multiples of 6 minutes and 9 minutes is 18 minutes
4:00 pm + 18 minutes
= 4:18 pm
The next time both shuttles will leave theairport together is 4:18 pm of the same day
I think he weighs 461.7 but I would check that
<h2>
Answer:</h2>
This is impossible to solve.
<h2>
Step-by-step explanation:</h2>
For an equation or inequality to be solvable, there must be the same number of inequalities as variables. Here, there is an x and there is a y. This means that you need at least two inequalities to solve it.
You can, however, rearrange to get x or y on one side.
This can be done for x:
5x < 10 + 2y
x < 2 + 2/5y
Or it can be done for y:
5x < 10 + 2y
5x - 10 < 2y
2.5x - 5 < y
Answer:
1.6 hours
Step-by-step explanation:
Number of opening hours a day = 8
Number of groups = 5
Dividing the number of opening. Hours equally among the 5 groups :
8 hours / 5
= 1.6 hours per group per day
