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Paha777 [63]
3 years ago
13

Please help with this question. I appreciate it

Mathematics
1 answer:
shusha [124]3 years ago
7 0

we are given

zeros : x=1 with multiplicity

so, we can write as

y=(x-1)^2

now, we are given

zeros : x=-2 with multiplicity =1

so,

y=(x-(-2))^1

now, we can combine them

and we get

f(x)=(x-1)^2(x-(-2))^1

f(x)=(x-1)^2(x+2).............Answer

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Part 2 - Find the error(s) and solve the problem correctly.
JulijaS [17]

The problem solved correctly as a single logarithm is log_{a} 2x^{3}/y^{2}

<h3>Simplifying Logarithm</h3>

From the question, we are to simplify the given logarithm

The given logarithm is

log_{a} 2x \ + \  2(log_{a} x -log_{a} y)

From the subtraction law of logarithm, we have that

log_{c} a -log_{c} b = log_{c} (a/b)

Thus,

The error in the solution was instead of multiplying, a was supposed to be divided by b

The correct solution is

log_{a} 2x \ + \  2(log_{a} x -log_{a} y)

log_{a} 2x \ + \  2(log_{a} (x/y) )

log_{a} 2x \ + \  log_{a} (x/y)^{2}

log_{a} 2x \ + \  log_{a} (x^{2}/y^{2})

Simplifying further

log_{a} 2x  \times (x^{2}/y^{2})

log_{a} 2x  \times x^{2}/y^{2}

log_{a} 2x^{3}/y^{2}

Hence, the problem solved correctly as a single logarithm is log_{a} 2x^{3}/y^{2}

Learn more on Simplifying logarithms here: brainly.com/question/247340

#SPJ1

3 0
2 years ago
What is the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81?
Marizza181 [45]

Answer: d. 1.3333

Step-by-step explanation:

We know that the standard error of a sampling distribution is given by :-

S.E.=\dfrac{\sigma}{\sqrt{n}}

, where \sigma = Population standard deviation.

n= Sample size.

AS per given , we have

\sigma =12

n=81

Then, the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81 will be :-

S.E.=\dfrac{12}{\sqrt{81}}

=\dfrac{12}{\sqrt{9^2}}=\dfrac{12}{9}\\\\=\dfrac{4}{3}\\\\\approx1.3333

Hence, the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81 is 1.3333.

Thus the correct answer is d. 1.3333 .

6 0
3 years ago
Help please. need it asap
Elan Coil [88]

Answer:

x = 180 - 50 - 86 = 44°

3 0
3 years ago
|14x – 1⁄3| = 2 solve
Tpy6a [65]

Answer:

It should be x=1/6- 5/12 i think

Step-by-step explanation:

4 0
3 years ago
Use a geometric formula to solve the problem.
Margaret [11]

The square length is 9.


a(area) =length times height


81=9 times 9


7 0
3 years ago
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