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GREYUIT [131]
3 years ago
14

Which steps could be used to solve this story problem?

Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0
She bought 3 pots of paint so
3×5
4 brushes so
4×3
and 3 pastel crayons so
3×13
Then add them all together to get your answer

It doesn't ask you to solve just describe how you'd solve
So your answer is C
You might be interested in
In the right triangle shown m
____ [38]

Answer:

we need a picture or something to look at to know what the question is

Step-by-step explanation:

6 0
3 years ago
Graph the image of the given triangle under a dilation with a scale factor of 1/3 and center of dilation (0, 0) .
Vinil7 [7]

We are given : A scale factor of 1/3 and center of dilation (0, 0).

For the given image, the coordinates of the vertices of the triangle are

(0,9), (0,0) and (-6,0).

We can apply formula for finding new coordinates:

Scale factor * [Vertex coordinates of the given image - Coordinate of Center of dilation] +Coordinate of Center of dilation.

Applying same formula to each coordinates we are given.

(0,9) --> 1/3 [ (0,9) - (0,0) ] + (0,0) ]  = 1/3 [ (0,9)] +(0,0) = (0,3).

(0,0) --> 1/3 [ (0,0) - (0,0) ] + (0,0) ]  = 1/3 [ (0,0] +(0,0) = (0,0).

(0,9) --> 1/3 [ (-6,0) - (0,0) ] + (0,0) ]  = 1/3 [ (-6,0)] +(0,0) = (-2,0).

Now, we can plot those resulting coordinates on the graph and form a triangle.


6 0
3 years ago
Read 2 more answers
Simplify 2X^3- 3x^2- 5x +3 / x+ 1
Maslowich

Answer:

-6x+3÷x+1

Step-by-step explanation:

2x^3-3x^2-5x+3÷x+1

2x ×2x ×2x-3x +3x-5x+3÷x+1

8x-9x-5x+3÷x+1

8x-14x+3÷x+1

-6x+3÷x+1


6 0
4 years ago
In the figure given below CP=x+3, PA=3x+19, CQ=x and QB=3x+4 then, what value of x will make PQ || AB?
zhenek [66]

Given that

PQ || AB

CP = x+3

PA = 3x+19

DC = x+3

CA = x

QB = 3x+4

We know that

By Basic Proportionality Theorem,

CP / PA = CQ / QB

On substituting these values in the above formula

⇛ (3x+19) / (x+3) = (3x+4) / x

On applying cross multiplication then

⇛ x(3x+19) = (3x+4)(x+3)

⇛ 3x²+19x = 3x(x+3)+4(x+3)

⇛ 3x²+19x = 3x²+9x+4x+12

⇛ 3x²+19x = 3x²+13x+12

⇛ 3x²+19x-3x²-13x = 12

⇛ (3x²-3x²)+(19x-13x) = 12

⇛ 0+6x = 12

⇛ 6x = 12

⇛ x = 12/6

⇛ x = 2

∴ , x = 2

<u>Answer:</u> The value of x for the given problem is 2

<em>Additional</em><em> comment</em><em>:</em>

<u>Basic Proportionality Theorem</u>

" A line drawn parallel to the one side of a triangle intersecting other two sides at two different points, then the line divides the other two sides in the same ratio".

<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> In the given figure QR ∥AB, RP∥ BD,CQ=x+2,QA=x,CP=5x+4,PD=3x.The value of x is..

brainly.com/question/18679712?referrer

brainly.com/question/18679661?referrer

6 0
2 years ago
If a right triangle's hypotenuse is 17 units long, and one of its legs is 15 units long, how long is the other leg?
Vesna [10]

Answer:

8 units

Step-by-step explanation:

Hello!

So, there's a formula we can apply to right-angled triangles: Pythagorean's theorem. It states that  c = \sqrt{{a}^2 + b^{2} }, where <em>c</em> is the hypotenuse and <em>a</em> and <em>b </em>are the legs of the triangle.

So, from the problem,  if <em>c </em>= 17 and <em>a </em> = 15, then, we're solving for <em>b</em>. So we'll rewrite the theorem to solve for <em>b</em>.

{c}^2 = {a}^2+{b}^2\\{c}^2-{a}^2={b}^2\\{b} = \sqrt{{c}^2-{a}^2}

Okay, so now we have isolated the theorem for <em>b. Let's </em>plug in our values for <em>c </em>and <em>a</em>.

b = \sqrt{{17}^2-{15}^2}\\b = \sqrt{289-225}\\b = \sqrt{64}\\b = 8

So, using the theorem, we found <em>b</em> = 8. To check our work, let's plug in <em>b</em> and <em>a</em> and solve for <em>c.</em>

<em />c = \sqrt{{a}^2+{b}^2}}\\c = \sqrt{{15}^2+{8}^2}\\c = \sqrt{225+64}\\c = \sqrt{289}\\c = 17\\<em />

So, we got our hypotenuse to equal 17 units, which is correct! So, our <em>b</em> is correct too. Awesome

7 0
3 years ago
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