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Finger [1]
3 years ago
12

Solve the following equations. 3 ⋅ 62^x = 648

Mathematics
1 answer:
gayaneshka [121]3 years ago
7 0

Answer:

x=1.56861

Step-by-step explanation:

62^x=648

By using logarithms it becomes easier to solve this question because of the properties they have

From the property of logarithms

loga^x=xloga

Take logarithms on both sides

log62^x=log648

\Rightarrow xlog62=log648

\Rightarrow x=\frac{log648}{log62}

\Rightarrow x=1.56861

x=1.56861

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three sets of the sum of a number and four are added to the sum of seven times the same number and thirteen
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<em><u>Solution:</u></em>

Given the statement:

Three sets of a sum of a number and four are added to the sum of seven times the same number and thirteen

Let us first understand the given statement,

Let the number be "x"

" sum of a number and four" means x + 4

"Three sets of a sum of a number and four" translated to 3(x + 4)

"sum of seven times the same number and thirteen" means 7x + 13

<em><u>Thus the algebraic expression for given statement is:</u></em>

3(x+4)+(7x + 13)

<em><u>Using distributive property in above expression</u></em>

a(b+c) = ab + bc

Therefore,

3(x+4)+(7x + 13) = 3x + 12 + 7x + 13

<em><u>Combine the like terms</u></em>

3(x+4)+(7x + 13) = 10x+25

Thus the required expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)

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Step-by-step explanation:

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Step-by-step explanation:

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