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geniusboy [140]
3 years ago
5

If a dart is thrown and hit inside the square. What is the probability

Mathematics
1 answer:
Ne4ueva [31]3 years ago
3 0

Answer: 50%

Step-by-step explanation:

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Which value of x is in the solution set of the following inequality?
andreyandreev [35.5K]

Answer:

C. 1

Step-by-step explanation:

Multiply every answer until you get an answer more than 6, and in this case it was C

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The Chang family is on
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I think is d correct answer 60%
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On Monday, the high temperature in Abilene was 75.6 degrees Fahrenheit and the high temperature in New York City was 54 degrees
madam [21]

Answer:

On monday,the high temperature in abilene was 75.6 degrees Fahrenheit and the temperature in New york city was 54 degrees Fahrenheit.How many times greater was the high tempareture in Abilene than the high temperature in New York on monday plz show your work

Step-by-step explanation:

3 0
3 years ago
A recent study examined the association between high blood pressure and increased risk of death from cardiovascular disease. The
zalisa [80]
<span>Find the odds of a man with high blood pressure dying from cardiovascular disease. 55 p .0165 3338 = p .0165 .0165 .0168 1 p 1 .0165 .9835

Do the same for a man with low blood pressure. 21 p .0079 2676 = = p .0079 .0079 .00796 1 p 1 .0079 .9921 = = = − − ----->

Calculate the odds ratio with the odds for the high blood pressure group in the numerator. Describe the result in words. HBP LBP odds .0168 odds ratio 2.11 odds .00796 = = = Men with high blood pressure are 2.11 times more likely to die from cardiovascular disease.</span>
7 0
3 years ago
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
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