Question

Given RS=6, ST=3, and SL=4, find the required measure. (Part of the answer is provided for you)

Answer 1

Given that RS = 6, ST = 3, and SL = 4, to find NS, we first find QS.

Notice that NQS forms a right triangle with the right andle at Q.

To find QS, we notice that QRS forms a right triangle with the right angle at R.

Note that ST = QR = 3 and RS = 6.

Using pythagoras theorem
$QS^2=QR^2+RS^2=3^2+6^2=9+36=45 \\ \\ QS=\sqrt{45}$

Note that NQ = SL = 4.

Using pythagoras theorem
$NS^2=NQ^2+QS^2=4^2 + 45=61 \\ \\ NS= \sqrt{61}$

Answer 2

Answer:

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Step-by-step explanation: