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kotykmax [81]
3 years ago
11

What is the 5% of 300

Mathematics
2 answers:
garik1379 [7]3 years ago
5 0
15
300*5/100 =15
That's all
almond37 [142]3 years ago
4 0
15.
the best way to do it is see the % as a decimal in my opinion, then plug it into a calculator. just move the decimal over to the left 2 times, then multiply the number you're taking the percent out of. So, in this case it would be:
300x.05
which is 15
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Mr.Smith is building a fence around his garden. The length is 3 feet longer than twice the width. The perimeter is 72 feet. Part
olga nikolaevna [1]

Step-by-step explanation:

A.C

B.2w + 2(w + 3) = 72

2w + 2w + 6 = 72

4w + 6 = 72

4w = 72 - 6

4w = 66

w = 16.5

5 0
3 years ago
Solve the system of equations by using substitution.
Nat2105 [25]

Answer:

(x, y) = (-1, 1)

Step-by-step explanation:

y = 2x +3  ----(1) \\\\y =  x + 2 ----(2)\\\\substitute \ (2) \ in \ (1) : x + 2 = 2x + 3

x - 2x = 3 - 2\\\\-x = 1\\\\x = -1\\\\Substitute \ x = -1 \ in  \ (2) : y = -1 + 2 => y = 1

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3 years ago
A number cube is labeled 1 through 6. What is the probability of NOT<br> rolling a 2?
Andre45 [30]

Answer:

Step-by-step explanation:

each of the 6 number has a 1/6 chance of being rolled

 1       2       3      4      5       6

1/6     1/6    1/6    1/6    1/6    1/6

Every time the cube is rolled  there is a 6/6 chance of any number comes up

1/6  +   1/6  +  1/6 +   1/6 +   1/6  +  1/6   = 6/6     or  1  

What is the probability of NOT rolling a 2? Any other number

 1        2       3        4        5         6

1/6  +   0  +  1/6 +   1/6  +  1/6 +   1/6   =   5/6    or    0.8333

5 0
3 years ago
A number is selected, at random, from the set {1,2,3,4,5,6,7,8}.
Olegator [25]

Applying the formula, you have:

A = the number is prime

B = the number is odd

I assume that with "random" you imply that all numbers can be chosen with the same probability. So, we have

P(A) = \dfrac{4}{8} = \dfrac{1}{2}

because 4 out of 8 numbers are prime: 2, 3, 5 and 7.

Similarly, we have

P(B) = \dfrac{4}{8} = \dfrac{1}{2}

because 4 out of 8 numbers are odd: 1, 3, 5 and 7.

Finally,

P(A \land B) = \dfrac{3}{8}

because 3 out of 8 numbers are prime and odd: 3, 5 and 7.

So, applying the formula, we have

P(\text{prime } | \text{ odd}) = \dfrac{P(\text{prime and odd})}{P(\text{odd})} = \dfrac{\frac{3}{8}}{\frac{1}{2}} = \dfrac{3}{8}\cdot 2 = \dfrac{3}{4}

Note:

I think that it is important to have a clear understanding of what's happening from a conceptual point of you: conditional probability simply changes the space you're working with: you are not asking "what is the probability that a random number, taken from 1 to 8, is prime?"

Rather, you are adding a bit of information, because you are asking "what is the probability that a random number, taken from 1 to 8, is prime, knowing that it's odd?"

So, we're not working anymore with the space {1,2,3,4,5,6,7,8}, but rather with {1,3,5,7} (we already know that our number is odd).

Out of these 4 odd numbers, 3 are primes. This is why the probability of picking a prime number among the odd numbers in {1,2,3,4,5,6,7,8} is 3/4: they are literally 3 out of 4.

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3 years ago
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Ivahew [28]

Answer:r=rrrrr=rrrrrrr=rrrrrrrrr=rrrrr=rrrrr=

Step-by-step explanation:

5 0
3 years ago
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