Question

Suppose we know that the birth weight of babies is Normally distributed with a mean 3500g and a standard deviation of 500g. What is the probability that a baby is born that weighs less than 3100g?

Answer 1

Answer:

0.21186

Step-by-step explanation:

We solve the above question using the z score formula.

z = (x-μ)/σ, where

x is the raw score = 3100g

μ is the population mean = 3500g

σ is the population standard deviation = 500g

z = 3100 - 3500/500

z = -0.8

Probability value from Z-Table:

P(x<3100) = 0.21186

The probability that a baby is born that weighs less than 3100g is 0.21186