Suppose we know that the birth weight of babies is Normally distributed with a mean 3500g and a standard deviation of 500g. What
is the probability that a baby is born that weighs less than 3100g?
1 answer:
Answer:
0.21186
Step-by-step explanation:
We solve the above question using the z score formula.
z = (x-μ)/σ, where
x is the raw score = 3100g
μ is the population mean = 3500g
σ is the population standard deviation = 500g
z = 3100 - 3500/500
z = -0.8
Probability value from Z-Table:
P(x<3100) = 0.21186
The probability that a baby is born that weighs less than 3100g is 0.21186
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