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MaRussiya [10]
3 years ago
10

Jamal drives 3 times the hours that Danielle does. Jamal and Danielle drive for a total of 8 hours. How long did each person dri

ve?
Mathematics
1 answer:
Lana71 [14]3 years ago
3 0

Answer: Danielle drive for 2 hours

Jamal drives for 2 × 3 = 6 hours

Step-by-step explanation:

Let the number of hours that Danielle used in driving to be represented by x.

Since Jamal drives 3 times the hours that Danielle does. This will be:

= 3 × x = 3x

Since Jamal and Danielle drive for a total of 8 hours. This can be formed into a equation as:

x + 3x = 8

4x = 8

x = 8/4

x = 2

Danielle drive for 2 hours

Jamal drives for 2 × 3 = 6 hours

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Please help I will give out brainliest
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Answer:

i)x=0,x=1

ii)

\frac{2}3} + \frac{\sqrt{40} }{6}  \\\frac{2}3}-\frac{\sqrt{40} }{6}

Step-by-step explanation:

so I did not use the graphs actually.

for the answer to question i), i wrote out the equation as given:

3x^2-3x+2=2

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3x^2-3x+2-2=+2-2, which becomes 3x^2-3x=0

then, I used the quadratic method of taking out the greatest common factor, which in this case is 3x, and the equation becomes:

3x(x-1)=0

finally, for this equation, I set 3x=0 and x-1 =0 to get the solutions to this equation, as shown below

3x=0(divide both sides by 3 to get)x=0

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now for the second equation, I had no other choice but to use the quadratic formula to find the solutions.

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3 years ago
1.___________a representation to show the total outcomes.
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By using the listing method, the number of possible uniforms that Brilliant Spa can choose from is equal to 9 uniforms.

<h3>What is a listing method?</h3>

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From the information provided above, we have the following points:

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By using the listing method, a list of all the elements in this data set is given by:

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6 0
2 years ago
An experiment consists of choosing objects without regards to order. Determine the size of the sample space when you choose the
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Answer:

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           n  =   \left N } \atop {}} \right.  C_r

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                           =     \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}

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           n  =   \left 25 } \atop {}} \right.  C_3 =  \frac{25 !}{(19 - 3 )! 3!}

                             =     \frac{25 *24 *23 *22 !  }{22 ! \ 3!}

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                              =     \frac{23 *22 *21!  }{21 ! \ 3!}

                              n =   253

4 0
4 years ago
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