Answer:
Step-by-step explanation:
If we take out the extra $3, we can group the bills into one each of $5 and $1, for a value of $6. There will be 7 such groups in the remaining $42.
That means there are 7 bills of the $5 denomination, and 3 more than that (10 bills) of the $1 denomination.
There are 7 $5 bills and 10 $1 bills.
_____
If you want to write an equation, it is usually best to let a variable stand for the most-valuable contributor. Here, we can let x represent then number of $5 bills. Then the value of the cash box is ...
5x +(x+3) = 45
6x = 42 . . . . . . . . subtract 3, collect terms
x = 7 . . . . . . . . . . . there are 7 $5 bills
x+3 = 10 . . . . . . . . there are 10 $1 bills
You may notice that this working parallels the verbal description above. (After we subtract $3, x is the number of $6 groups.)
164.38 = (1 x 100) + (6 x 10) + (4 x 1) + (3/10) + (8/100)
9ths answer. 113.112 ~ 113.1
The answer is 69 dollars and the titian would be 69 dollas
Answer:
dy/dx = -1/
Step-by-step explanation:
y = 1/x
dy/dx = d/dx(1/x)
=> dy/dx = d/dx(
)
=> dy/dx = -
=> dy/dx = -1/
