Answer:
-9 may be the right answer
Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
;)
Answer:
k = -3
Step-by-step explanation:
1) Simplify
5+20k+7k=28k+8
2) Combine the k's
5+27k=28k+8
3) Subtract 27k on both sides
5=k+8
4) Subtract 8 on both sides
-3=k or k= -3
Answer:
I think √170
Step-by-step explanation:
The points are A: (-3,5) and (4,-6) so we plug this into the distance formula
√(x2-x1)^2+(y2-y1)^2
√(4-(-3))^2+(-6-5)^2
√(7)^2+(-11)^2=
√49+121= √170 or a really long decimal which starts out 13.038404810
If I got the points wrong I can redo the problem and get another answer but I did the problem on my own and used a calculator and got the same answer
