Answer:
Step-by-step explanation:
can i pls have brainliest??
Answer:
1 or 5
Step-by-step explanation:
Given the function h(x)=(2x−2)(x−5)
The zeros of h(x) are the values of x for which h(x)=0
h(x)=(2x−2)(x−5)=0
Note that if a.b=0, either a=0 or b=0.
Appying the above,
If (2x−2)(x−5)=0
Then:
2x−2=0 or x-5=0
2x=2 or x=5
x=1 0r 5
The zeroes of h(x) as defined are 1 or 5.
Answer:
Intersection point of this is (0,-0.5)
Step-by-step explanation:
Hope this helps :)
Answer:
The second one
Step-by-step explanation:
Answer:
probably where 2004 is??
Step-by-step explanation: