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Vladimir [108]
3 years ago
6

Someone help a sister out

Mathematics
1 answer:
myrzilka [38]3 years ago
3 0
X= 14 for the top
x= -2 for the bottom
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the company president sets a goal that the percentage of working phones must increase from 30% to at least 80% by the end of the
MArishka [77]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
Which expression is equivalent to: <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B200%7D" id="TexFormula1" title="\sqrt[3]{2
Alja [10]

Answer:

The answer is b.

2 \sqrt[3]{25}

7 0
3 years ago
Read 2 more answers
Find the value of x in the triangle shown below.<br> a. x=80<br> b. x=48<br> c. x= 32<br> d. x=12
yulyashka [42]

THEOREM:

• <u>Pythagorean theorem</u>:— In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides.

ANSWER:

By pythagorean property,

x² = 4² + 8²

x² = 16 + 64

x² = 80

x = √80 units.

So, <u>Correct choice</u> - [A] √80 units.

8 0
3 years ago
Read 2 more answers
(Geometry course question) Explain why it is not possible to construct an equilateral triangle that has
Nutka1998 [239]

Answer:

  √3 is irrational

Step-by-step explanation:

The location of the third point of a triangle can be found using a rotation matrix to transform the coordinates of the given points.

<h3 /><h3>Location of point C</h3>

With reference to the attached figure, the slope of line AC is √3, an irrational number. This means the line AC <em>never passes through a point with integer coordinates</em>. (Any point with integer coordinates would be on a line with rational slope.)

<h3>Equilateral triangle</h3>

The line segments making up an equilateral triangle are separated by an angle of 60°. If two vertices are on grid squares, the third must be a rotation of one of them about the other through an angle of 60°. The rotation matrix is irrational, so the rotated point must have irrational coordinates.

The math of it is this. For rotation of (x, y) counterclockwise 60° about the origin, the transformation matrix is ...

  \left[\begin{array}{cc}\cos(60^\circ)&\sin(60^\circ)\\-\sin(60^\circ)&\cos(60^\circ)\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{c}x'\\y'\end{array}\right]

Cos(60°) is rational, but sin(60°) is not. For any non-zero rational values of x and y, the sum ...

  cos(60°)·x + sin(60°)·y

will be irrational.

As in the attached diagram, if one of the coordinates of the rotated point (B) is zero, then one of the coordinates of its image (C) will be rational. The other image point coordinate cannot be rational.

6 0
2 years ago
Compute: (1 2/5 +3.5÷1 1/4 )÷2 2/5 +3.4÷2 1 /8 −0.35
nikdorinn [45]

Answer:

Answer: 3

Step-by-step explanation:

Use BODMAS

<u>Step 1: Open bracket (1 2/5 +3.5÷1 1/4 )</u>

<em>Convert mixed fractions into improper fractions</em>

7/5 + 3.5 ÷ 5/4

<em>Divide 3.5 by 5/4</em>

7/5 + 2.8 = 4.2

<u>Step 2: Carry out all divisions</u>

<em>Convert mixed fraction into improper fractions</em>

4.2 ÷2 2/5 +3.4÷2 1 /8 −0.35

4.2 ÷ 12/5 + 3.4 ÷ 17/8 - 0.35

1.75 + 1.6 - 0.35

<u>Step 3: Solve</u>

1.75 + 1.6 - 0.35

3.35 - 0.35

Answer = 3

4 0
3 years ago
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