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Aleonysh [2.5K]
3 years ago
8

Tj Ate 100 time on the slide and breelyn slide down 20 time and marlin slide down1 Time how many slide did to and breelyn and ma

rine went down 100 + 20 =120
Mathematics
1 answer:
Ray Of Light [21]3 years ago
3 0

Answer:

120

Step-by-step explanation:

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Answer:

I don't see attachment

Step-by-step explanation:

3 0
3 years ago
Sherri has 23 pieces of jewelry to sell. She sells the bracelets for $2 and the necklaces for $3, and earns a total of $55. If t
Nutka1998 [239]
X + y = 23
2x + 3y = 55
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3 years ago
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❗️❗️URGENT❗️❗️<br> 24. Find slope of the line.<br> A. 3/2<br> B. -3/2<br> C. -2/3<br> D. 2/3
Dvinal [7]

Answer:

Option (A)

Step-by-step explanation:

Slope of a line passing through two points (x₁, y₁) and (x₂, y₂) is given by,

Slope = \frac{y_2-y_1}{x_2-x_1}

Form the graph attached,

Graphed line passes through two points (0, 1) and (-2, -2),

Therefore, slope of the line passing through these points will be,

Slope = \frac{1+2}{0+2} = \frac{3}{2}

Option (A) will be the answer.

4 0
3 years ago
Value of 50 ÷ (4 + 6) • 4 ??
FinnZ [79.3K]

Answer:

20

Step-by-step explanation:

PEMDAS

Parentheses: (4+6)= 10

Division: 50/10=5

Multiplication: 5*4=20

4 0
3 years ago
Read 2 more answers
Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank
mars1129 [50]

Complete question:

Consider 3 boxes, each of which contains 4 balls in particular, box 1 contains 4 white balls, box 2 contains 3 white balls and 1 red ball, box 3 contains 2 white balls and 2 red balls. Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank extracts 2 balls with replacement. USE ONLY THE CONDITIONAL PROBABILITY FORMALISM and derive an expression for the probability that the 2 extracted balls are red.

Answer:

11/288

Step-by-step explanation:

We are given:

Box 1: ( 4White, ORed)

Box 2: (3White, 1Red)

Box 3: (2White, 2 Red)

We are told that if Frank choose from Box 1 and Box 3, 2 balls are extracted without replacement.

Since there is no red ball in Box 1, there is no way 2 red balls will come out from Box1.

Our Event, E = getting 2 red balls.

Now Box 1 is ruled out, we have:

P[E(B1)]= 0

P[E/B3)] = (2 2) / (4 2)

= 1/6

If box 2 is chosen, 2 balls are extracted with replacement. Therefore for Box 2:

P(E/B2) = (1/4) *(1/4)

= 1/16

Therefore probability that 2 balls extracted are red, we have:

P(E)=P(E/B1) P(B1) + P(E/B2) P(B2)+P(E/B3) P(B3)

= 0 * \frac{1}{3} + \frac{1}{6}*\frac{1}{3} + \frac{1}{16}*\frac{1}{3}

= 11/288

3 0
3 years ago
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