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3 years ago

What is the slope of the line through (1, -1) and (5. – 7)?

Mathematics

2 answers:

SpyIntel [72]3 years ago

8 0

Answer:

m=-2

Step-by-step explanation:

Vladimir [108]3 years ago

6 0

Answer:

-3/2

Step-by-step explanation:

Given two points, we can find the slope by

m = (y2-y1)/(x2-x1)

= (-7 - -1)/ (5-1)

= (-7+1)/(5-1)

= -6/4

= -3/2

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Which of the following has a graph that is a stight line?

Y_Kistochka [10]

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equation 3- does a stight line
equation 4- you sure that right

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3 years ago

Sharon is planning a holiday for 4 people for 7 days.

Eduardwww [97]

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3 years ago

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Evaluate the function for x=4 F(x)= x^3+2x^2+1

alukav5142 [94]

Answer:

F(4) = 97

Step-by-step explanation:

F(x)= x³+2x²+1

when x = 4

F(4)= 4³+2(4²)+1

= 4³+2(4²)+1

= 64 + 2(16) + 1

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3 years ago

BRAINLIEST!! NEED AN ANSWER ASAP!! HELPP

Nata [24]

No; a range value has two domain values.

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3 years ago

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I need help on 17 and 23 pls

ludmilkaskok [199]

Question # 17 Solution

Answer:

$x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Step-by-step Explanation:

The given expression

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

And we have to solve for x₁

So,

Lets solve for x₁.

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Multiply both sides by x₂ - x₁

$m(x_{2}-x_{1})= (x_{2}-x_{1})\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m(x_{2}-x_{1})= (y_{2}-y_{1})$

$mx_{2}-mx_{1}= (y_{2}-y_{1})$

$-mx_{1}= y_{2}-y_{1}-mx_{2}$

Divide both sides by -m

$\frac{-mx_{1}}{-m}= \frac{y_{2}-y_{1}-mx_{2}}{-m}$

$x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Therefore, $x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Question # 23 Solution

Answer:

$n= \frac{bx}{-b + x}$

Step-by-step Explanation:

The given expression

$\frac{nx}{b}-x=x$

And we have to solve for n

So,

Let's solve for n.

$\frac{nx}{b}-x=x$

Multiply both sides by b.

$-bn + nx = bx$

Factor out n.

$n(-b + x)= bx$

Divide both sides by -b + x.

$\frac{n(-b + x)}{-b + x}= \frac{bx}{-b + x}$

$n= \frac{bx}{-b + x}$

Therefore, $n= \frac{bx}{-b + x}$

Keywords: solution, equation

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6 0

4 years ago