Material=wall+2*side and material is 40 ft so:
40=w+2s
w=40-2s
Area=ws, using w from above we get:
A=(40-2s)s
A=40s-2s^2
dA/ds=40-4s and d2A/ds2=-4
Since d2A/ds2 is a constant negative acceleration, when dA/ds=0, A(s) is at an absolute maximum.
dA/ds=0 when 4s=40, s=10 ft
And since w=40-2s, w=20 ft
So the dimensions of the pen are 20 ft by 10 ft, with the 20 ft side being opposite the wall. And the maximum possible area is thus 200 ft^2
The domain in this equation is -7<x<infinty and the range is negative infinty<y<1.5
3x + 2y + y - 3x = 180
3y = 180
y = 180/3
y = 60
3x = y - 3x
Let y = 60
3x = 60 - 3x
3x + 3x = 60
6x = 60
x = 60/6
x = 10
Answer: x = 10, y = 60
It’s c) XS, i love your pfp btw!! :)
The distance is 8 you just have to measure off of the y axis
