Answer:
The area of one trapezoidal face of the figure is 2 square inches
Step-by-step explanation:
<u><em>The complete question is</em></u>
The point of a square pyramid is cut off, making each lateral face of the pyramid a trapezoid with the dimensions shown. What is the area of one trapezoidal face of the figure?
we know that
The area of a trapezoid is given by the formula

where
b_1 and b-2 are the parallel sides
h is the height of the trapezoid (perpendicular distance between the parallel sides)
we have

substitute the given values in the formula


<span>(x – h)^2 + (y – k)^2 = r<span>^2
this equation is a derivative of the equation of a circle
x^2 + y^2 = r^2
This is from the origin. If we move the in x or y then the radius will change positions in x or y
with h = -3 and k = 1
we can plug in each set of numbers and solve.
we find Z to be on the circle edge!</span></span>
F(x) = x^2 - 3x - 8
f(-2) = (-2)^2 - 3 (-2) - 8
f(-2) = 4 - 3 (-2) - 8
f(-2) = 4 + 6 - 8
f(-2) = 10 - 8
f(-2) = 2 ✅