3 years ago

Help please maybe !!??

Mathematics

2 answers:

Bumek [7]3 years ago

7 0

Yeah the picture is very blurry, can’t read it all, sorry. Can you try send again?

Reptile [31]3 years ago

5 0

Sorry but i can barely see it! Try taking a better picture, or a screenshot

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4 years ago

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2 years ago

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PolarNik [594]

$\bf \textit{Law of Cosines}\\\\ c^2 = a^2+b^2-(2ab)cos(C)\implies c = \sqrt{a^2+b^2-(2ab)cos(C)} \\\\\\ \cfrac{a^2+b^2-c^2}{2ab}=cos(C)\implies cos^{-1}\left(\cfrac{a^2+b^2-c^2}{2ab}\right)=\measuredangle C\\\\ -------------------------------$

$\bf \begin{cases} a=90\\ b=55\\ c=50 \end{cases}\implies cos^{-1}\left(\cfrac{b^2+c^2-a^2}{2bc}\right)=\measuredangle A \\\\\\ cos^{-1}\left(\cfrac{55^2+50^2-90^2}{2(55)(50)}\right)=\measuredangle A\implies cos^{-1}\left(\cfrac{-2575}{5500} \right)=\measuredangle A \\\\\\ 117.91634^o\approx \measuredangle A$

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3 years ago