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True [87]
3 years ago
13

Which of the following is NOT a fate for pyruvate?

Chemistry
1 answer:
son4ous [18]3 years ago
6 0

Answer: The conversion to malate  

Explanation:

Pyruvate is the process which produced in glycoysis which has multiple fates and it can give rises to acetyl co-enzyme and undergo the aerobic oxidation in the critic acid cycle. It can be used to produces glucose but it never produced the malate. In prokaryotes it can be processes in the anaerobic respiration to produced the ethanol, as end product.

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Rank the ions in order of increasing basicity: CH3NH-, CH3CH2-, CH30-
Alexxx [7]

In order to find out the ranking of ions basicity, check the pKa values of each ions. The principle that you need to remember is that the stronger the acid the weaker the corresponding conjugate base. The pKa dictates acid value of the compound. The answer would be CH3NH, CH3O-, and CH3CH2-. 

3 0
3 years ago
I am having some trouble figuring out how to approach the following problem: A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is ti
Tanya [424]
<span>We look at the end of the day:

n(HNO3) added = 0.500*17.0/1000 = 0.00850 mol
n(NH3) = 0.200*75.0/1000 - 0.00850 = 0.00650 mol
[NH3] left = 0.00650*1000/(17.0+75.0) = 0.070652
M [OH-] = Kb * [NH3] = 0.070652*1.8*10^(-5) = 1.27174 x 10^(-6)
pOH = -log[OH-] ≈ 5.8956 pH = 14 - pOH ≈ 8.10</span>
4 0
3 years ago
Let’s assume that you put a balloon into the freezer. Initially,the balloon had 3.0liters of gas at a pressure of 400kPa and was
EastWind [94]
Here, we should use combined gas law which can be derived from combined gas law, “PV=nRT”. Rearranging, we can get PV/T=nR. Then we can set the two states in the problem together to get

P1V1/T1 = P2V2/T2

Then just plug in and solve algebraically.

Hope this helps
6 0
3 years ago
(a) Calculate the total volume (in liters) of air an adult breathes in a day. (b) In a city with heavy traffic, the air contains
Furkat [3]

Answer:

a) V air/day = 8640 L air  an adult breaths / day

b) 0.0181 L CO intake a person / day

Explanation:

a) one average person has 12 breaths for min:

  • P = 12 breath/min

in each breath it take an average  of 500 mL on air.

  • 1 breath ≅ 500 mL air

⇒ 12 breath / min * 500mL air / breath = 6000 mL air / min

the average air volume per day of a person is:

⇒ Vair/day = 6000 mL air / min * (60 min / h) * ( 24 h / day ) = 8640000 mLair / day * ( L / 1000 mL)

⇒ V air / day = 8640 L / day

b) 2.1 E-6 L CO / L air * 8640 L air / day = 0.0181 L CO / day

4 0
3 years ago
If the pressure of 50.0 mL of oxygen gas at 100°C increases from 735 mm Hg to 925 mm Hg, what is
laila [671]

Answer: .039L

Explanation:

8 0
3 years ago
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