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2 years ago

Question #1: Identify the type of Mutation below

Chemistry

1 answer:

borishaifa [10]2 years ago

5 0

Answer:

Deletion

Explanation:

A mutation refers to a change in the DNA sequence. This means that the original sequence of bases in the DNA has been altered permanently.

There are three types of DNA mutations; base substitutions, deletions and insertions.

In the particular case of this question, the original is TTCGATA while the copy is TTGATA. If you look closely at the two, you will notice that the C has been omitted. This is an example of deletion.

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A beaker is filled to the 500 mL mark with alcohol. What increase in volume (in mL) does the beaker contain when the temperature

Aliun [14]

Answer:

"1.4 mL" is the appropriate solution.

Explanation:

According to the question,

$v_0=500$
$\alpha =1.12\times 10^{-4}$
$\Delta \epsilon = 25$

Now,

Increase in volume will be:

⇒ $\Delta V = \alpha\times v_0\times \Delta \epsilon$

By putting the given values, we get

$=1.12\times 10^{-4}\times 500\times 25$

$=1.12\times 10^{-4}\times 12500$

$=1.4 \ mL$

8 0

3 years ago

In an investigation with density, Marcia’s teacher measures the mass and volume of 10 different samples of a substance. The samp

valina [46]

Answer:

Mass

Step-by-step explanation:

Usually, you plot the independent variable along the horizontal (x) axis and the dependent variable along the vertical (y) axis.

Marcia's teacher plotted the mass of the sample along the x-axis and volume along the y-axis.

The mass is the independent variable, because that is what the teacher varied.

The volume is the dependent variable, because it depends on the mass.

Sample number is wrong, because it is not a variable.

Substance is wrong, because all samples consist of the same substance.

Density is wrong, because it is constant. It is the slope of the graph.

3 0

2 years ago

Read 2 more answers

A student has the following data recorded: final readings: 760. mm Hg, 6.0L, 197 'C. initial readings:

irina [24]

Is that Geometry or Algebra?

7 0

2 years ago

The question is in the picture below

Rus_ich [418]

Answer:

$\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3$

Explanation:

Hess's Law of Constant Heat Summation states that if a chemical equation can be written as the sum of several other chemical equations, the enthalpy change of the first chemical equation is equal to the sum of the enthalpy changes of the other chemical equations. Thus, the reaction that involves the conversion of reactant A to B, for example, has the same enthalpy change even if you convert A to C, before converting it to B. Regardless of how many steps it takes for the reactant to be converted to the product, the enthalpy change of the overall reaction is constant.

With Hess's Law in mind, let's see how A can be converted to 2C +E.

$\bf{\text{A} \rightarrow 2\text{B}}$ (Δ $\text{H}_1$ ) -----(1)

Since we have 2B, multiply the whole of II. by 2:

$\bf{2\text{B} \rightarrow 2\text{C} +2\text{D}}$ (2Δ $\text{H}_2$ ) -----(2)

This step converts all the B intermediates to 2C +2D. This means that the overall reaction at this stage is $\text{A} \rightarrow 2\text{C} +2\text{D}$ .

Reversing III. gives us a negative enthalpy change as such:

$\bf{2\text{D} \rightarrow \text{E}}$ (-Δ $\text{H}_3$ ) -----(3)

This step converts all the D intermediates formed from step (2) to E. This results in the overall equation of $\text{A} \rightarrow 2\text{C} +\text{E}$ , which is also the equation of interest.