Answer:
Step-by-step explanation:
If the square has an area of 49 ft^2, then the length of one of its sides is
s = √(49 ft^2) = 7 ft, and its perimeter is P = 4(7 ft) = 28 ft.
As for the rectangle: let W and L represent the width and length, respectively. Then W*L = 24 ft^2 is the area. L = W + 2 ft. Therefore,
W(W + 2) = 24, or W^2 + 2W - 24 = 0, or (W +6)(W - 4) = 0. Thus, W = 4 ft.
The perimeter of this rectangle is P = 2W + 2L, or
P = 2(4 ft) + 2(6 ft) = 24 ft.
The square has the larger perimeter: It is 28 ft.
X=3 y=5 hope this helped :)
Answer:
In Δ CFD , CD is the LONGEST side.
Step-by-step explanation:
Here, the given Δ CSD is a RIGHT ANGLED TRIANGLE.
Now, as we know in a right triangle, HYPOTENUSE IS THE LONGEST SIDE.
So, in Δ CSD SD is the longest side as SD = Hypotenuse.
Now, an altitude CF is drawn to hypotenuse SD.
⇒ CF ⊥ SD
⇒ Δ CFD is a RIGHT ANGLED TRIANGLE with ∠ F = 90°
and CD as a hypotenuse.
⇒ In Δ CFD , CD is the LONGEST side.
Hence, CD is the longest side in the given triangle CFD.