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4 years ago

Hi someone please solve this

Mathematics

1 answer:

pshichka [43]4 years ago

6 0

Answer:

x = 115

Step-by-step explanation:

If lines are parallel, alternate interior angles are congruent (the same measure). Since this is a parallelogram, opposite sides are parallel, and AIA is applicable, so x = 115 degrees.

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Suppose we have four integers, no two of which are congruent $\pmod 6$. Let $N$ be the product of the four integers. If $N$ is n

aalyn [17]

Answer:

Step-by-step explanation:

Given:

A, B, C, D have distinct positive values for mod 6

A (mod 6) = 1

B (mod 6) = 2

C (mod 6) = 4

D (mod 6) = 5

Each mod 6 value cannot be a zero since the product ABCD is not a multiple of 6.

Furthermore, in order that ABCD mod 6 > 0, we cannot have a residue equal to 3, else the product with a residue 2 or 4 will make the product a multiple of 6.

Thus the only positive residues can only be 1,2,4,5

A*B*C*D (mod 6) > 0 = 1*2*4*5 (mod 6) = 4

4 0

4 years ago

I NEED HELP AND QUICK.

Gnom [1K]

Answer:

1. 40-p+w

2. $4 left

I'm not sure about the first one, but I'm pretty sure about the second one.

Step-by-step explanation:

8 0

3 years ago

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

$y=a(x+1)(x-5)=0$

This gives

$x=-1$

$y=5$

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

$B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}$

Thus the coordinates of B are:

$B=(-1+\frac{2\sqrt{3} }{3},2)$

Now this point B lies on the parabola, and therefore it must satisfy the equation $y=a(x+1)(x-5).$

Thus

$2=a((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)$

Therefore

$a=\frac{2}{((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)}$

$\boxed{a=-0.3575}$

8 0

3 years ago

1. a model rocket is fired vertically into the air at 320 ft/s. The expression -16t^2+320t gives the rocket's height after t sec

zloy xaker [14]

1A.) Cannot Be Factored

2B.) 7n(2n + 7 + n)

3C.) (b+3) (2b + 5)

4D.) -(xy - 2x + 12)

5E.) (r-5)(7r^2+6)

7 0

3 years ago

If the ratio of the length to perimeter is 5:16 what is the area of the rectangle

salantis [7]

The area is 15
Multiply the length by 2
5(2)
Subtract the length from the perimeter
16-10
Divide the remainder by 2 to find the width
6/2
The width is 3
Length times width equals area
3(5)=15

8 0

3 years ago