Answer:
≈ 0.52
Step-by-step explanation:
P( head ) = 2/3 , P( tail ) = 1/3
when a head is tossed ; Gambler A wins $1
when a tail is tossed : Gambler B wins $1
<u>Determine the P( Gambler A wins the game ) if he starts with I dollars</u>
Assuming I = $1
n = 5
p ( head ) = P( winning ) = 0.66
p( losing ) = 0.33
applying the conditional probability in Markov which is ;
Pₓ = pPₓ₊₁ + (1 - p) Pₓ₋₁
P( 1) = 0.66P₂ + 0.33P₀
resolving the above using with Markov probability
P( 1 ) = 0.51613
hence the probability of Gambler A winning the game if he starts with $1
≈ 0.52
-9 to the second power will most likely be 81. A negative x a negative equals a positive. Hope this helped.
The answer i think is. If<span> the </span>length<span> of the </span>table<span> is </span>18 ft more than<span> the </span>width<span>, </span>x, which - 1447102. ... Thearea<span> of the </span>conference table<span> in </span>Mr<span>. </span>Nathan's office must<span> be </span>no more than 175 ft2<span> ... Therefore, the</span>interval<span> 0 < </span>x<span> ≤ 7 represents the possible widths</span>
It is d, -8.-5. I did it on paper
Answer:
B.)
Step-by-step explanation:
that is a characteristic of a maximum value parabola.
