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loris [4]
3 years ago
8

Evaluate 0.1(3.7) using distributive proper

Mathematics
2 answers:
zzz [600]3 years ago
6 0
To solve  0.1(3.7) using distributive property you can do:
 (0.1*3.0)+(0.1*0.7)
OR
0.1(3.00+0.70)

HOPE IT HELPS YOU!
krek1111 [17]3 years ago
4 0
To solve this you simply multiply 0.1 by 3.7
0.1×3.7= 0.37 
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Ok, so dy/dx=0 at the point (0,3) that is where x=0 and y=3.

\int { 6x+6dx } \\ \\ =\frac { 6{ x }^{ 2 } }{ 2 } +6x+C\\ \\ =3{ x }^{ 2 }+6x+C

\\ \\ \therefore \quad { f }^{ ' }\left( x \right) =3{ x }^{ 2 }+6x+C

Now, f'(x)=0 when x=0.

Therefore:

0=C\\ \\ \therefore \quad { f }^{ ' }\left( x \right) =3{ x }^{ 2 }+6x

Now:

\int { 3{ x }^{ 2 } } +6xdx\\ \\ =\frac { 3{ x }^{ 3 } }{ 3 } +\frac { 6x^{ 2 } }{ 2 } +C

={ x }^{ 3 }+3{ x }^{ 2 }+C\\ \\ \therefore \quad f\left( x \right) ={ x }^{ 3 }+3{ x }^{ 2 }+C

But when x=0, y=3, therefore:

3=C\\ \\ \therefore \quad f\left( x \right) ={ x }^{ 3 }+3{ x }^{ 2 }+3
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