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3 years ago

Solve the question: 3(.5y-6)=12

Mathematics

1 answer:

makvit [3.9K]3 years ago

6 0

Answer:

y = 20.

Step-by-step explanation:

Distribute:

$3(0.5y)-3(6)=12$

$1.5y-18=12$

Add 18 to both sides:

$1.5y-18+18=12+18$

$1.5y=30$

Solve for y:

$\frac{1.5y}{1.5}=\frac{30}{1.5}$

$y=20$

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4 years ago

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3 years ago

During the final 5 seconds of a race a cyclist increased her velocity from 4 m/s to 7 m/s . What was her average acceleration du

GREYUIT [131]

Answer:

The average acceleration of the cyclist was 0.6 m/s².

Step-by-step explanation:

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The rate change of velocity per unit time is call the acceleration of the object.

$a=\frac{v-u}t$

u= initial velocity

v= final velocity

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3 years ago

Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif

dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

Step:-1

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals $t_{0.01} =2.82$ (from tabulated value).

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$x±t_{0.01} \frac{S}{\sqrt{n-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{22} }$

$0.0365±2.82 \frac{0.0046}{4.690 }$

using calculator

$0.0365±0.00276$

Confidence interval is

$(0.0365-0.00276,0.0365+0.00276)$

$(0.0338,0.0392)$

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Answer:-

using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.

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3 years ago

Solve the question: 3(.5y-6)=12​

Solve the question: 3(.5y-6)=12