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saw5 [17]
3 years ago
5

Solve the question: 3(.5y-6)=12​

Mathematics
1 answer:
makvit [3.9K]3 years ago
6 0

Answer:

y = 20.

Step-by-step explanation:

Distribute:

3(0.5y)-3(6)=12

1.5y-18=12

Add 18 to both sides:

1.5y-18+18=12+18

1.5y=30

Solve for y:

\frac{1.5y}{1.5}=\frac{30}{1.5}

y=20

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What is 3 1/2 - 2 5/7 and show the work
Hunter-Best [27]
3 \frac{1}{2}  -2 \frac{5}{7} = \frac{(3\cdot2)+1}{2} -  \frac{(2\cdot7)+5}{7} =  \frac{7}{2} -  \frac{19}{7} \\\\= \frac{7\times 7}{2\times 7} -  \frac{19\times 2}{7\times 2} =  \frac{49}{14} - \frac{38}{14} \\\\= \frac{49-38}{14} =\boxed{\bf{\frac{11}{14}}}
6 0
3 years ago
Please help pls pls help pls belp
Delvig [45]

Answer:

After 1 second, the ball will reach a maximum height of 16 feet

Step-by-step explanation:

The height of the ball after t seconds: h(t) = -16t^2 + 32t

The graph of this quadratic function is parabola which opens downwards. The vertex of a quadratic equation is the maximum or minimum point on the equation's parabola

t = -b/2a = -(32)/2(-16) = -32/-32 = 1 second

then

h(t) = -16(1)^2 + 32(1) = -16 + 32 = 16

After 1 second, the ball will reach a maximum height of 16 feet

8 0
2 years ago
Find the highest common factor(HCF) of 18 and 24
prisoha [69]
18 - 2,3,6,8
24 - 2,4,6,8,12

HCF = 8
6 0
3 years ago
a standard deck of cards missing the queen of hearts in the 2 of clubs what is the probability of pulling either an ace or a spa
Butoxors [25]
<h3>Answer:  8/25</h3>

=======================================================

Explanation:

In a standard deck, there are 52 cards.

If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.

There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.

Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.

-----------------

The event space has A = 16 cards in it, while the sample space has B = 50 cards.

The probability we're after is A/B = 16/50 = 8/25

5 0
2 years ago
What is the most precise name for a quadrilateral with the following vertices:
lozanna [386]

Answer:

The most precise name for a quadrilateral ABCD is a parallelogram

Step-by-step explanation:

we have

A(2,3) B(7,2) C(6,-1) D(1,0)

Plot the quadrilateral'

using a graphing tool

The quadrilateral ABCD in the attached figure

Verify the length of the sides

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find distance AB

A(2,3) B(7,2)

substitute

d=\sqrt{(2-3)^{2}+(7-2)^{2}}

d=\sqrt{(-1)^{2}+(5)^{2}}

d_A_B=\sqrt{26}\ units

step 2

Find distance BC

B(7,2) C(6,-1)

substitute

d=\sqrt{(-1-2)^{2}+(6-7)^{2}}

d=\sqrt{(-3)^{2}+(-1)^{2}}

d_B_C=\sqrt{10}\ units

step 3

Find distance CD

C(6,-1) D(1,0)

substitute

d=\sqrt{(0+1)^{2}+(1-6)^{2}}

d=\sqrt{(1)^{2}+(-5)^{2}}

d_C_D=\sqrt{26}\ units

step 4

Find distance AD

A(2,3) D(1,0)

substitute

d=\sqrt{(0-3)^{2}+(1-2)^{2}}

d=\sqrt{(-3)^{2}+(-1)^{2}}

d_A_D=\sqrt{10}\ units

step 5

Compare the length sides

AB=CD

BC=AD

Opposite sides are congruent

<em>Verify the slope of the sides</em>

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find slope AB

A(2,3) B(7,2)

substitute

m=\frac{2-3}{7-2}

m=\frac{-1}{5}

m_A_B=-\frac{1}{5}

step 2

Find slope BC

B(7,2) C(6,-1)

substitute

m=\frac{-1-2}{6-7}

m=\frac{-3}{-1}

m_B_C=3

step 3

Find slope CD

C(6,-1) D(1,0)

substitute

m=\frac{0+1}{1-6}

m=\frac{1}{-5}

m_C_D=-\frac{1}{5}

step 4

Find slope AD

A(2,3) D(1,0)

substitute

m=\frac{0-3}{1-2}

m=\frac{-3}{-1}

m_A_D=3

step 5

Compare the slopes

m_A_B=m_C_D

m_B_C=m_A_D

The slope of the opposite sides are equal, that means, opposite sides are parallel

The slopes of consecutive sides are not opposite reciprocal, that means, consecutive sides are not perpendicular

therefore

The most precise name for a quadrilateral ABCD is a parallelogram

8 0
3 years ago
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