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saw5 [17]
3 years ago
5

Solve the question: 3(.5y-6)=12​

Mathematics
1 answer:
makvit [3.9K]3 years ago
6 0

Answer:

y = 20.

Step-by-step explanation:

Distribute:

3(0.5y)-3(6)=12

1.5y-18=12

Add 18 to both sides:

1.5y-18+18=12+18

1.5y=30

Solve for y:

\frac{1.5y}{1.5}=\frac{30}{1.5}

y=20

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2 years ago
Help, please!!<br><br><br> How much is 2/5 of 20 ?
Alex787 [66]

Question

Help, please!!

How much is 2/5 of 20 ?


Answer:

8

Step-by-step explanation:

20 * 2/5 =

8

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20 : 5 * 2 = 8


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3 years ago
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3 years ago
In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini
svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2

The augmented matrix is

\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]

The reduction of this matrix to row-echelon form is outlined below.

R_2\rightarrow R_2-R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]

R_3\rightarrow R_3-2R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]

R_3\rightarrow R_3-R_2

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]

The last row determines, if there are solutions or not. To be consistent, we must have k such that

k^2-k-2=0

\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2

Case k = −1:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]

This gives the infinite many solution.

5 0
3 years ago
Can anyone help me x55x5x5x56x6x7x7= ?<br><br> this is for my gf
77julia77 [94]

Answer:x 55x5x5x56x6x7x74 4,527,600

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3 years ago
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