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Keith_Richards [23]
3 years ago
8

Nitroglycerine decomposes violently according to the unbalanced chemical equation below. How many total moles of gases are produ

ced from the decomposition of 1.00 mol C3H5(NO3)3?C3H5(NO3)3 --> CO2(g) + N2(g) + H2O(g) + O2(g)
4.00 mol
6.50 mol
7.25 mol
16.5 mol
29.0 mol
Physics
1 answer:
Sedaia [141]3 years ago
4 0

<u>Answer:</u> The total number of moles of gases produced are 7.25 moles.

<u>Explanation:</u>

The chemical reaction for the decomposition of C_3H_5(NO_3)_3 follows the equation:

4C_3H_5(NO_3)_3\rightarrow 12CO_2(g)+6N_2(g)+10H_2O(g)+O_2(g)

We are given:

Moles of C_3H_5(NO_3)_3 = 1.00 mol

  • <u>For carbon dioxide:</u>

By Stoichiometry of the reaction:

4 moles of C_3H_5(NO_3)_3 is producing 12 moles of carbon dioxide.

So, 1 mole of C_3H_5(NO_3)_3 will produce = \frac{12}{4}\times 1=3mol of carbon dioxide.

Moles of carbon dioxide produced = 3 moles

  • <u>For nitrogen:</u>

By Stoichiometry of the reaction:

4 moles of C_3H_5(NO_3)_3 is producing 6 moles of nitrogen.

So, 1 mole of C_3H_5(NO_3)_3 will produce = \frac{6}{4}\times 1=1.5mol of nitrogen.

Moles of nitrogen produced = 1.5 moles

  • <u>For water:</u>

By Stoichiometry of the reaction:

4 moles of C_3H_5(NO_3)_3 is producing 10 moles of water.

So, 1 mole of C_3H_5(NO_3)_3 will produce = \frac{12}{10}\times 1=2.5mol of water.

Moles of water produced = 2.5 moles

  • <u>For oxygen:</u>

By Stoichiometry of the reaction:

4 moles of C_3H_5(NO_3)_3 is producing 1 moles of oxygen.

So, 1 mole of C_3H_5(NO_3)_3 will produce = \frac{1}{4}\times 1=0.25mol of oxygen.

Moles of oxygen produced = 0.25 moles

Total number of moles of the gases produced are = 3 + 1.5 + 2.5 + 0.25 = 7.25 moles.

Hence, the total number of moles of gases produced are 7.25 moles.

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