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Drupady [299]
4 years ago
8

What are two reasons why density is a useful physical property for identifying substances?

Physics
1 answer:
padilas [110]4 years ago
4 0
Some substances look alike and the density can help you determine which is which. It also helps to tell which is heavier than the other.
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Example of what happens to particles when their kinetic energy decreases?
Ann [662]

Explanation:

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3 years ago
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The work done on an elevator that has a mass of 1000kg and lifted 4m in 10 seconds is how many joules.
GaryK [48]

Answer:

39,200 Joules

3920 watts

Explanation:

5 0
4 years ago
What is the quantity of charge that passes through a conductor when there is a current of 0.25 A for 10 minutes?
nikitadnepr [17]
To calculate charge(Q) through a point, we multiply the current(I) with time (t)
Thus, Q= It
Therefore, t must be in SI units which gives 60*10 seconds.
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4 0
3 years ago
Given vectors D (3.00 m, 315 degrees wrt x-axis) and E (4.50 m, 53.0 degrees wrt x-axis), find the resultant R= D + E. (a) Write
Eva8 [605]

Answer:

  • R = ( 4.831 m , 1.469 m )
  • Magnitude of R = 5.049 m
  • Direction of R relative to the x axis= 16°54'33'

Explanation:

Knowing the magnitude and directions relative to the x axis, we can find the Cartesian representation of the vectors using the formula

\vec{A}= | \vec{A} | \ ( \ cos(\theta) \ , \ sin (\theta) \ )

where | \vec{A} | its the magnitude and θ.

So, for our vectors, we will have:

\vec{D}= 3.00 m \ ( \ cos(315) \ , \ sin (315) \ )

\vec{D}=  ( 2.121 m , -2.121 m )

and

\vec{E}= 4.50 m \ ( \ cos(53.0) \ , \ sin (53.0) \ )

\vec{E}= ( 2.71 m , 3.59 m )

Now, we can take the sum of the vectors

\vec{R} = \vec{D} + \vec{E}

\vec{R} = ( 2.121 \ m , -2.121 \ m ) + ( 2.71 \ m , 3.59 \ m )

\vec{R} = ( 2.121 \ m  + 2.71 \ m , -2.121 \ m + 3.59 \ m )

\vec{R} = ( 4.831 \ m , 1.469 \ m )

This is R in Cartesian representation, now, to find the magnitude we can use the Pythagorean theorem

|\vec{R}| = \sqrt{R_x^2 + R_y^2}

|\vec{R}| = \sqrt{(4.831 m)^2 + (1.469 m)^2}

|\vec{R}| = \sqrt{23.338 m^2 + 2.158 m^2}

|\vec{R}| = \sqrt{25.496 m^2}

|\vec{R}| = 5.049 m

To find the direction, we can use

\theta = arctan(\frac{R_y}{R_x})

\theta = arctan(\frac{1.469 \ m}{4.831 \ m})

\theta = arctan(0.304)

\theta = 16\°54'33''

As we are in the first quadrant, this is relative to the x axis.

3 0
4 years ago
An object is dropped from a very tall bridge. If it takes 29.48 s to reach the ground below, how high is the bridge?////
LenKa [72]

Answer:

ithe bridge is about 3.01 or exactly 3.0081632653

5 0
4 years ago
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