<span>Which is a gas at room temperature?
</span>B) nitrogen
Answer:
14 m/s
Explanation:
The following data were obtained from the question:
Mass = 50 kg
Initial velocity (u) = 0 m/s
Height (h) = 10 m
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) =?
The velocity (v) with which the person hit the water can be obtained as shown below:
v² = u² + 2gh
v² = 0² + (2 × 9.8 × 10)
v² = 0 + 196
v² = 196
Take the square root of both side
v = √196
v = 14 m/s
Therefore, he will hit the water with a speed of 14 m/s
A wave as long as matter is not being transported
Answer:
a magnet being moved into or out of the coil
Explanation:
Electromagnetic induction on a coil of wire depends on relative motion between the wire and a magnetic field. If there is no relative motion between the magnet and the coil, no current is included on the wire. This implies that a stationary magnet around a coil of wire will not produce induced current on a stationary conductor or wire.
Summarily, whenever a conductor is placed in a changing magnetic field, current is induced on the conductor.
To solve the problem it is necessary to apply the concepts related to thermal expansion of solids. Thermodynamically the expansion is given by

Where,
Original Length of the bar
= Change in temperature
= Coefficient of thermal expansion
On the other hand our values are given as,




Replacing we have,



The width of the expansion of the cracks between the slabs is 0.5832cm