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FrozenT [24]
3 years ago
12

Current evidence suggests that many massive jovian planets orbit at very close orbital distances to their stars. How do we think

these planets ended up on these close orbits?
Physics
1 answer:
ivanzaharov [21]3 years ago
4 0

Answer:

In the Solar system, the Jovian planets are farther from the Sun. Majority of the extrasolar Jovian planets are closer to their stars. These are known as "Hot Jupiters". From the studies, the reason for the existence of massive Jovian planets to be closer to their star is found to be the gravitational interaction of these planets with other massive planets which pushes them closer to their stars. These planets are formed beyond the frost line initially but later on migrate inwards.

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What is the opposition to the flow of AC produced by a magnetic field with generated back voltage (EMF) called?
jek_recluse [69]

Answer and Explanation :

The opposition of the flow of alternating current produced by a magnetic field is called inductive reactance it is denoted by X_L, The value of the inductive reactance depends on the value of inductance. The good thing about inductive reactance is that it is not responsible for the power loss as  resistance is responsible for the power loss  

5 0
4 years ago
A stick of mass m and length / is pivoted at one
AfilCa [17]

Answer:

  • Potential Energy = mgl (1 - cosθ)

Explanation:

<h3>Given :-</h3>
  • Mass of stick = m
  • Length of stick = l
  • Angle = θ

<h3>To Find :-</h3>
  • Increase potential energy

<h3>Solution :-</h3>

✪ <u>According to the given </u><u>data</u> :-

 ⠀⠀⠀→ cosθ = ᵇ/ₕ

 ⠀⠀⠀→ cosθ = ᴬᴮ/l

 ⠀⠀⠀→ AB = l cosθ

❂ <u>For </u><u>Height</u> :-

 ⠀⠀⠀→ h = l - l cosθ

 ⠀⠀⠀→ h = l (1-cosθ)

☯ <u>As we know that</u>

 ⠀⠀⠀→ Potential Energy = mgh

 ⠀⠀⠀→ Potential Energy = mg × l (1-cosθ)

 ⠀⠀⠀→ Potential Energy = mgl (1-cosθ)

5 0
3 years ago
Is a baseball and cannon are dropped from the same height at the same time, which ball will hit the ground first?
lara31 [8.8K]
If you include the effects of falling through air, then you have to know the
shape, size, weight, and surface texture of the objects.  You also have to
know the height from which they're dropped, and the temperature, pressure,
and humidity of the air.  All these things make a difference in how they fall.

If you ignore the effects of falling through air, like build a giant metal tank
and pump all the air out of it, and ONLY talk about the effects of gravity, then
ALL OBJECTS accelerate at the same rate.  If you drop two things from the
same height at the same time, then they both hit the ground at the same time,
traveling at the same speed, no matter what they are.  They could be a piece of
tissue and a car ! 

There are several museums where they have a big glass pipe that you can
see through, and they pump the air out of the pipe and drop a feather and a
bowling ball from the top inside at the same time, and they both reach the
bottom together.   

If gravity is the only force on an object, then all objects fall at the same rate.
8 0
4 years ago
Read 2 more answers
A star is estimated to be 4.8 km away from the earth. When we see this star in the night sky how old is the image. Let the speed
andre [41]

Time = distance / speed

Time = (4,800 meters) / (3 x 10⁸ m/s)

<em>Time = 0.000016 second</em>

This number is not one of the choices on the list.  My hunch is that you copied the distance wrong.

If the estimated distance to the star is actually 4.8 x 10¹⁵ km, instead of 4.8 km, then the answer would be close to 500 years <em>(B)</em>.

There's no way a star can be "4.8 km away from the Earth".  You can <em>walk</em> that far in about an hour, and passenger jet airplanes fly <em>twice</em> as far as that away from the Earth !

5 0
3 years ago
Spheres of Charge: A metal sphere of radius 10 cm carries an excess charge of +2.0 μC. What is the magnitude of the electric fie
nadezda [96]

To solve this problem we will apply the concept related to the electric field.  The magnitude of each electric force with which a pair of determined charges at rest interacts has a relationship directly proportional to the product of the magnitude of both, but inversely proportional to the square of the segment that exists between them. Mathematically can be expressed as,

E = \frac{kV}{r^2}

Here,

k = Coulomb's constant

V = Voltage

r = Distance

Replacing we have

E = \frac{(9*10^9)(2*10^{-6})}{((10+5)*10^{-2})^2}

E = 8*10^5N/C

Therefore the magnitude of the electric field is 8*10^5N/C

4 0
3 years ago
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