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FrozenT [24]
3 years ago
12

Current evidence suggests that many massive jovian planets orbit at very close orbital distances to their stars. How do we think

these planets ended up on these close orbits?
Physics
1 answer:
ivanzaharov [21]3 years ago
4 0

Answer:

In the Solar system, the Jovian planets are farther from the Sun. Majority of the extrasolar Jovian planets are closer to their stars. These are known as "Hot Jupiters". From the studies, the reason for the existence of massive Jovian planets to be closer to their star is found to be the gravitational interaction of these planets with other massive planets which pushes them closer to their stars. These planets are formed beyond the frost line initially but later on migrate inwards.

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Suppose the tip of the minute hand of a clock is two inches from the center of the clock. Determine the distance traveled by the
sashaice [31]
1) The minute travels the circumference of a 4 inches circle is 60 minutes:

Circumference = 2πr = 2π(2in) = 4π in
Time = 60 minutes

2) Constant angular velocity => (4π / 60) = (x / 20) => x = 4π / 3 inches

x = 4.19 inches

Answer: 4.19 inches

4 0
3 years ago
A frictionless cart of mass M is attached to a spring with spring constant k. When the cart is displaced 6 cm from its rest posi
Marianna [84]

Answer:

Time period of horizontal Oscillation  = T = 2\pi\sqrt{\frac{m}{k} }

As you can see, from the equation, Period of oscillation depends upon the mass and the spring constant. Not on the displacement.

Explanation:

Solution:

As we know that:

F = Kx

Here,

K = Spring constant

x = displacement.

First, they are displacing it with 6 cm from its rest position for which Time period of the oscillation is T = 2 seconds.

But next, they want to know the effect on the time period of the oscillation if the displacement x is doubled from 6cm to 12 cm.

First of all, let us see the equation of the time period of the oscillation.

We need to check, if time period does depend on the displacement or not.

As we know,

Time period of horizontal Oscillation  = T = 2\pi\sqrt{\frac{m}{k} }

As you can see, from the equation, Period of oscillation depends upon the mass and the spring constant. Not on the displacement.

Since, K is the constant for a particular spring, we need to change the mass of the cart to change the time period.

Hence the Time period will remain same.

8 0
3 years ago
How high would a projectile go if it was launched from ground level with an initial speed of 26 m/s at an angle of 30 degrees ab
tigry1 [53]

Answer:

Vy = 26 m/s sin 30 = 13 m/s      vertical speed

t = Vy / a = 13 m/s / 9.80 m/s^2 = 1.33 sec     time to reach Vy = 0

H = Vy t + 1/2 g t^2

H = 13 m/s * 1.33 sec - 1.33^2 * 9.8 / 2 m = 8.62 m

4 0
1 year ago
The spirit rover could move across the Martian landscape at a maximum of 2.68 m/mi. How many minutes would it take for it to tra
satela [25.4K]

Answer:

Explanation:

Thks for answer

3 0
2 years ago
HELP When the forces are applied in the same direction, how do you determine net force?
aleksklad [387]

Answer:

Explanation:

If two forces act on an object in the same direction, the net force is equal to the sum of the two forces.

5 0
3 years ago
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