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FrozenT [24]
3 years ago
12

Current evidence suggests that many massive jovian planets orbit at very close orbital distances to their stars. How do we think

these planets ended up on these close orbits?
Physics
1 answer:
ivanzaharov [21]3 years ago
4 0

Answer:

In the Solar system, the Jovian planets are farther from the Sun. Majority of the extrasolar Jovian planets are closer to their stars. These are known as "Hot Jupiters". From the studies, the reason for the existence of massive Jovian planets to be closer to their star is found to be the gravitational interaction of these planets with other massive planets which pushes them closer to their stars. These planets are formed beyond the frost line initially but later on migrate inwards.

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A substance that is present in a solution in a smaller amount and is dissolved by the solvent is called the solute.
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3 years ago
An electric motor is rated at 900 W. How much force does it apply when moving
brilliants [131]
<h3>Answer:  7.74 newtons</h3>

========================================

Steps Shown:

Work = Force*Displacement

Power = Work/Time

Power = (Force*Displacement)/Time

900 W = (F*1000 m)/(8.6 sec)

900 = (F*1000)/8.6

900*8.6 = 1000F

7740 = 1000F

1000F = 7740

F = 7740/1000

F = 7.74 newtons

6 0
3 years ago
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3 years ago
Define universal vibrations ?​
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4 0
2 years ago
Read 2 more answers
Car A is traveling west at 40 mi/h and car B is traveling north at 40 mi/h. Both are headed for the intersection of the two road
Gwar [14]

Explanation:

It is given that,

    \frac{dx}{dt} = -40 mi/h,     \frac{dx}{dt} = -40 mi/h

The negative sign indicates that x and y are decreasing.

We have to find \frac{dz}{dt}. Equation for the given variables according to the Pythagoras theorem is as follows.

              z^{2} = x^{2} + y^{2}

Now, we will differentiate each side w.r.t 't' as follows.

        2z\frac{dz}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}

or,          \frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})

So, when x = 4 mi, and y = 3 mi then z = 5 mi.

As,       \frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})

                       = \frac{1}{5}(4 \times (-40) + 3 \times (-40))

                       = \frac{-140 - 120}{5}

                       = 52

Thus, we can conclude that the cars are approaching at a rate of 52 mi/h.

7 0
3 years ago
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