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3 years ago

6

A 1000-kg car rolling on a smooth horizontal surface ( no friction) has speed of 20 m/s when it strikes a horizontal spring and

is brought to rest in a distance of 2 m What is the spring’s stiffness constant?

1 answer:

spayn [35]3 years ago

6 0

Explanation:

kinetic energy was converted to potential energy in the spring.

the answer is in the above image

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Please help I don't know how to answer these questions!

Yuki888 [10]

1) The potential energy is the most at the highest position and the least at the equilibrium position

2) The kinetic energy is the most at the equilibrium position and the least at the highest position

Explanation:

1)

The potential energy of an object is the energy possessed by the object due to its position in a gravitational field; mathematically, it is given by

$PE=mgh$

where

m is the mass of the object

g is the strength of the gravitational field

h is the height of the object relative to the ground

For the pendulum in this problem, m is the mass of the bob, and h is the height of the above relative to the ground. We see from the formula that the potential energy is directly proportional to the height:

$PE\propto h$

This means that:

The potential energy is the most when the bob is at the highest position
The potential energy is the least when the bob is at the equilibrium position, which is the lowest position

2)

We can solve this part by applying the law of conservation of energy: in fact, the total mechanical energy of the pendulum (sum of potential and kinetic energy) is constant at any time during the motion,

$E=KE+PE=const.$

where KE is the kinetic energy.

From the equation above, we observe that:

When PE is maximum, KE must be at minimum
When PE is minimum, KE must be maximum

Therefore, this implies that:

The kinetic energy is the most when the potential energy is the least, i.e. at the equilibrium position
The kinetic energy is the least when the potential energy is the most, i.e. at the highest position

Learn more about kinetic and potential energy:

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#LearnwithBrainly

6 0

3 years ago

Simple Circuit and Ohm's Law Check-for-Understanding

Vanyuwa [196]

Answer:

current, only

Explanation:

current:I

voltage:U

resistance:R

formula: I=U/R

Increasing the battery cause the increasing in the voltage. Resistance does not normally change. And the current would increase.

4 0

3 years ago

Read 2 more answers

Can someone explain the normal force? where does it come from? ...?

Vilka [71]

<span>The normal force is the support force exerted upon an object which is in contact with another stable object. For example, if a book is resting upon a surface, then the surface is exerting an upward force upon the book in order to support the weight of the book. The normal force in itseñf comes from the third law of Newton as a reactive force</span>

6 0

3 years ago

A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum

s2008m [1.1K]

Answer:

241.7 s

Explanation:

We are given that

Charge of particle= $q=-2.74\times 10^{-6} C$

Kinetic energy of particle= $K_E=6.65\times 10^{-10} J$

Initial time= $t_1=6.36 s$

Final potential difference= $V_2=0.351 V$

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

$qV=K.E$

Using the formula

$2.74\times 10^{-6}V_1=6.65\times 10^{-10} J$

$V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V$

Initial voltage= $V_1=2.43\times 10^{-4} V$

$\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2$

Using the formula

$\frac{V_1}{V_2}=(\frac{6.36}{t})^2$

$\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}$

$t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}$

$t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}$

$t=241.7 s$

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

6 0

3 years ago

The curve below shows the percentage of population of aquatic species that die in response to doses of pollutant A:

Elis [28]

Based on the trend produced by the dose - response graph, it would be best to evacuate the residents in other to prevent the increasing percentage of deaths due to the rising level of pollutant A.

The curve shows that the pollutant level in mg/kg of pollutant A is still increasing, hence, groundwater monitoring alone won't be the best decision to make.

Since the pollutant level is still increasing, then the spill level still need effective monitoring.

Evacuation of residents seems to be the best decision that should be taken based on the information interpreted on the graph.

Therefore, Evacuating residents to prevent rising death percentage is required as the pollutant level is yet to subside.

Learn more :brainly.com/question/24844489

8 0

2 years ago