Answer:
Do you have options? The answer would be
g(x)=(x/3)^2
x = 1 btw
Because x = 1, if you have options then it'll most likely be g(x)=(1/3]^2
Step-by-step explanation:
Hope this helps
No, because negative base sometimes results in non-real or imaginary value.
Substitute each value of x in y=2x-3
so,
first box (-2)
y= 2(-2)-3
y= -4-3
y= -7
second box (0)
y= 2(0)-3
y= 0-3
y= -3
third box (3)
y=2(3)-3
y=6-3
y=3
Answer:
definition the set of positive real number which greater than 0 are the nonnegative number. for ex=(1,2,3...10)
Answer:
I can't see the whole question.