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iragen [17]
4 years ago
13

Tank a has a capacity of 9.5 galloons 6 1/3 gallons of the tanks water are poured out how many gallons of water are left in the

tank
Mathematics
2 answers:
Ivenika [448]4 years ago
6 0

3\frac{1}{6} gallons are left in the tank.

  • Total capacity of the tank = 9.5 gallons
  • Total amount of water poured out in gallons = 6\frac{1}{3}
<h2>Further Explanation</h2>

To determine the total amount left in the tank = Total capacity of the tank – Total amount of water poured out in gallons

= 9.5 (also expressed as 95/10) – 6\frac{1}{3} (otherwise expressed as \frac{19}{3} )

Before solving further, we look for the lowest common denominator (LCD) of both denominators (10 and 3) since we are dealing with fractions.

Hence,

LCD of 10 and 3 = 30

Therefore,

= \frac{95}{10} – \frac{19}{3}  

= (95 x 3) – (19 x 10) / 30

= (285) – (190) / 30

= 285 – 190 / 30

= \frac{95}{30}

= \frac{19}{6}

= 3\frac{1}{6} gallons  

Thus, the total amount of gallons of water left in the tank is 3\frac{1}{6} gallons.

The above expression is a typical number problem which has an element of fraction in it. Fraction consists of numerator and denominators which are usually jointly factored out to derive a solution to a given math problem.

It is essential to apply BODMAS while solving a fraction problem like the one given. And notably, the arms of BODMAS that were applied are Division, Multiplication and Addition.

LEARN MORE:

  • What does BODMAS stand for brainly.com/question/9352422
  • Numbers: brainly.com/question/2906770
  • fraction brainly.com/question/6201432

KEYWORDS:

  • 9.5 galloons
  • 6 1/3 gallons
  • gallons of water
  • tank
  • bodmas
  • numbers
  • fraction
Alisiya [41]4 years ago
3 0
= 9 \frac{1}{2} - 6 \frac{1}{3} \\ = 9 \frac{3}{6} - 6 \frac{2}{6}
= 3 \frac{3 - 2}{6} \\ = 3 \frac{1}{6}

3 1/6 gallons of water are left in the tank.
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