Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
I think it should be option d
Where is the question? Is it a true or false?
You forgot to add in your height to your question. To find your area you need to do 8 + 14 and get 22 then you nee to do the height divided by two. If you give me the height of the triangle I can tell you the area.
Answer:
Step-by-step explanation:
60 x 60 = 3600
3600 x 24
5280 x 12
I know for steps 2 and 3 to be equal, 3600 would have to be half of 5280 because 24 is twice 12, and it’s not. And because 3600 is more than half of 5280, I know that 3600 times 24 is more than 5280 times 12. My answer, therefore, is there are more seconds in a day.
