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White raven [17]
3 years ago
5

What is the slope of the line that is parallel to the y-axis and passes through the point (–1, 5)?

Mathematics
2 answers:
sertanlavr [38]3 years ago
6 0
<span>What is the slope of the line that is parallel to the y-axis and passes through the point (–1, 5)?

check the picture below.

the y-axis is a vertical line, thus any line parallel to it, will also be a vertical line, so, let's pick another point, hmmmmm say -1, 3, thus

</span>\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ -1 &,& 5~) &#10;%  (c,d)&#10;&&(~ -1 &,& 3~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope =  m\implies &#10;\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-5}{-1-(-1)}\implies \cfrac{3-5}{-1+1}\implies \stackrel{und efined}{\cfrac{-2}{0}}<span>
</span>

Nitella [24]3 years ago
4 0
Undefined because the slop of the y axis is undefined
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2 years ago
I really need some help. I need to find the inverse of this equation in the picture below. Thanks!
serg [7]

Answer:

y=81x^4+648x^3+1944x^2+2592x+1289

Step-by-step explanation:

1. Interchange x and y.

  • y=\frac{\sqrt[4]{x+7}}{3}-2
  • x=\frac{\sqrt[4]{y+7}}{3}-2

2. Then solve x=\frac{\sqrt[4]{y+7}}{3}-2 for y.

3. y=81x^4+648x^3+1944x^2+2592x+1289

I hope this helps.

4 0
2 years ago
Find the 7th term of the sequence 1,5/4,25/16
lutik1710 [3]

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Answer:

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Step-by-step explanation:

The sequence is geometric with first term 1 and common ratio 5/4. The general term is ...

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7 0
3 years ago
I need help finding if it’s either SOH, CAH or TOA and the indicated side of the triangle, thank you!
Brilliant_brown [7]

Answer:

\huge\boxed{IJ \approx 2.01}

Step-by-step explanation:

In order to find the side mentioned (IJ), we need to use SOH CAH TOA.

SOH CAH TOA is an acronym to help us remember what sin, cos, and tan mean. It stands for:

Sin = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tan = Opposite / Adjacent

Since we know the measure of angle K (42) and we know one of the sides, we can use this to find the missing length.

Since the side given to us is the hypotenuse, and we're looking for the side opposite of the angle (IJ), the only possible one to use would be SIN as it includes Opposite and Hypotenuse.

Our equation is now this: \text{sin(42)} = \frac{x}{3}

Let's now solve for x.

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Therefore, the length of IJ will be around 2.01.

Hope this helped!

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